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Ray Of Light [21]
3 years ago
6

Rachel jogged along a trail that was 1/4 (fraction) of a mile long. She jogged along the trail 8 times. How many miles did Rache

l jog in all??
Mathematics
2 answers:
OverLord2011 [107]3 years ago
5 0
1/4+1/4+1/4+1/4+1/4+1/4+<span>1/4+1/4 = 8 Miles

1/4+1/4 = 1/2 Mile

1/2+1/2 = 1 Mile

1+1 = 2 Miles</span>
Murrr4er [49]3 years ago
4 0
2 miles because 8 divided by 1/4 is 2
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Answer:

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Step-by-step explanation:

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3 years ago
In the △ABC, the height AN = 24 in, BN = 18 in, AC = 40 in. Find AB and BC. Consider all possible cases. Case 1 : N∈BC, AB = __,
aivan3 [116]

Answer:

Case 1:

AB = 30

BC = 50

Case 2:

AB = 15.9

BC = 36.7

Case 3: Not possible

Step-by-step explanation:

Given

See attachment for illustration of each case

Required

Find AB and BC

Case 1:

Using Pythagoras theorem in ANB, we have:

AB^2 = AN^2 + BN^2

This gives:

AB^2 = 24^2 + 18^2

AB^2 = 576 + 324

AB^2 = 900

Take square roots of both sides

AB = \sqrt{900

AB = 30

To calculate BC, we consider ANC, where:

AC^2 = AN^2 + NC^2

40^2 = 24^2 + NC^2

1600 = 576 + NC^2

Collect like terms

NC^2 = 1600 - 576

NC^2 = 1024

Take square roots

NC = \sqrt{1024

NC = 32

So:

BC = NC + BN

BC = 32 + 18

BC = 50

Case 2:

Using Pythagoras theorem in ANB, we have:

AN^2 = AB^2 + BN^2

This gives:

24^2 = AB^2 + 18^2

576 = AB^2 + 324

Collect like terms

AB^2 = 576 - 324

AB^2 = 252

Take square roots of both sides

AB = \sqrt{252

AB = 15.9

To calculate BC, we consider ABC, where:

AC^2 = AB^2 + BC^2

40^2 = 252 + BC^2

1600 = 252 + BC^2

Collect like terms

BC^2 = 1600 - 252

BC^2 = 1348

Take square roots

BC = \sqrt{1348

BC = 36.7

Case 3:

This is not possible because in ANC

The hypotenuse AN (24) is less than AC (40)

3 0
2 years ago
Determine if the sequence is arithmetic. If it is, find the term named in the problem.
Brums [2.3K]

Answer:

a_{39} <em>= 279</em>

Step-by-step explanation:

a_{n} = a_{1} + (n - 1)d

d = a_{2} - a_{1}

~~~~~~~~~

d = - 17 + 25 = - 9 + 17 = - 1 + 9 = 8

a_{39} = - 25 + 8(39 - 1) = 279

a_{39} <em>= 279</em><em> </em>

5 0
3 years ago
Consider the system of equations.
jok3333 [9.3K]

Given:

The system of equations:

x-3y=9

\dfrac{1}{5}x-2y=-1

To find:

The number that can be multiplied by the second equation to eliminate the x-variable when the equations are added together.

Solution:

We have,

x-3y=9                        ...(i)

\dfrac{1}{5}x-2y=-1       ...(ii)

The coefficient of x in (i) and (ii) are 1 and \dfrac{1}{5} respectively.

To eliminate the variable x by adding the equations, we need the coefficients of x as the additive inverse of each other, i.e, a and -a So, a+(-a)=0.

It means, we have to convert \dfrac{1}{5} into -1. It is possible if we multiply the equation (ii) by -5.

On multiplying equation (ii) by -5, we get

-x+10y=5       ...(iii)

On adding (i) and (iii), we get

7y=14

Here, x is eliminated.

Therefore, the number -5 can be multiplied by the second equation to eliminate the x-variable.

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2 years ago
How do I find GD? Giving Brainly
77julia77 [94]

Answer:

cut it in half, your answer is 11

3 0
2 years ago
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