Only selections B and D give a maximum height of 13 at t=3. However, both of those functions have the height be -5 at t=0, meaning the ball was served from 5 ft below ground. This does not seem like an appropriate model.
We suspect ...
• the "correct" answers are probably B and D
• whoever wrote the problem wasn't paying attention.
Answer:
(4,-2)
Step-by-step explanation:
plug in and simplify;
y+2=-3(x-4)
-2+2=-3(x-4)
0=-3x+12
3x=12
x=4
We know that
the slope formula is
m=(y2-y1)/(x2-x1)
(x1,y1)=(0,2)
(x2,y2)=(x,0)
m=1-----> equation 1
m=(0-2)/(x-0)------> m=-2/x -----> equation 2
equate equation 1 and equation 2
1=-2/x------> multiply by x both sides------> x=-2
the point (x2,y2) is ----------> (-2,0)
Answer:
B. The typical value is greater in set A. The spread is greater in set B.