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sesenic [268]
3 years ago
6

Add parenthesis to the expression to equal 7. 3x2+6

Mathematics
1 answer:
lakkis [162]3 years ago
4 0

Answer:

(3times2)+6

Step-by-step explanation:

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What is the approximate area of the unshaded region under the standard normal curve below? Use the portion of the standard norma
Harlamova29_29 [7]

The approximate area of the unshaded region under the standard normal curve is 0.86 the option third is correct.

It is given that the standard normal curve shows the shaded area in the curve.

It is required to find the approximate area of the unshaded region under the standard normal curve.

<h3>What is a normal distribution?</h3>

It is defined as the continuous distribution probability curve which is most likely symmetric around the mean. At Z=0, the probability is 50-50% on the Z curve. It is also called a bell-shaped curve.

In the curve showing the shaded region area between:

\rm P(1 < Z < 2)

First, we calculate the shaded region area:

From the data given the value of Ф(1) = 0.8413.

P(Z<1)  = 0.8413  and

P(Z<2) =  0.9772

The area of the shaded region:

= P(Z<2) - P(Z<1)

=  0.9772 - 0.8413

= 0.1359

The area of the unshaded region:

= 1 - The area of the shaded region  ( because the curve is symmetric)

= 1 - 0.1359

= 0.8641 ≈ 0.86

Thus, the approximate area of the unshaded region under the standard normal curve is 0.86 the option third is correct.

Know more about the normal distribution here:

brainly.com/question/12421652

4 0
2 years ago
What is the slope of the graph y = -25x - 42?​
sweet [91]
-25x is the slope
-42 is the y-intercept
5 0
3 years ago
Read 2 more answers
Someone please help me on this I have 5 minutes!
Alla [95]

Answer: A. sqrt of 500.

Step-by-step explanation: If you simplify the sqrt of 500, you will get 10 sqrt of 5

5 0
2 years ago
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Find an equation, or a set of equations, to describe the set of points that are equidistant from the points p(−9, 0, 0) and q(3,
wariber [46]
X = -3.  
The distance from p(-9, 0, 0) is
 d = sqrt((x+9)^2 + y^2 + z^2) 
 The distance from q(3,0,0) is
 d = sqrt((x-3)^2 + y^2 + z^2) 
 Let's set them equal to each other.
 sqrt((x+9)^2 + y^2 + z^2) = sqrt((x-3)^2 + y^2 + z^2)
  Square both sides, then simplify
 (x+9)^2 + y^2 + z^2 = (x-3)^2 + y^2 + z^2
 x^2 + 18x + 81 + y^2 + z^2 = x^2 - 6x + 9 + y^2 + z^2
 18x + 81 = - 6x + 9
 24x + 81 = 9
 24x = -72
 x = -3 
 So the desired equation is x = -3 which defines a plane.
7 0
3 years ago
Can you please answer this for me
Vsevolod [243]

Answer:

you are on the right track

Step-by-step explanation:

the second ones right so you are right :)

3 0
3 years ago
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