Answer:
$38
Step-by-step explanation:
Since the last two numbers aren't over 50, we would round down. This leaves you with $38.
Answer:
trapezoid
Step-by-step explanation:
parallelograms require two sets of parallel lines while trapezoids do not, only requiring one set. it is possible to get a trapezoid with 2 90 degree angles.
In this item, we are to calculated for the 6th term of the geometric sequence given the initial value and the common ratio. This can be calculated through the equation,
An = (A₀)(r)ⁿ ⁻ ¹
where An is the nth term, A₀ is the first term (in this item is referred to as t₀), r is the common ratio, and n is the number of terms.
Substitute the known values to the equation,
An = (5)(-1/2)⁶ ⁻ ¹
An = -5/32
Hence, the answer to this item is the third choice, -5/32.
Answer:
39
Step-by-step explanation:
To find the intervals you will need to find the lowest and highest numbers, in this case, it would be 1 and 35. A general rule would be 5-7 intervals, I will use 5.
Here are the intervals with the number of people that were in each:
1-7 (9)
8-14 (14)
15-21 (8)
22-28 (3)
29-35 (5)
14+9+8+3+5=39
9514 1404 393
Answer:
10
Step-by-step explanation:
Let L and T represent the initial amounts that Leo and Theo had. Let n represent the number of bills exchanged in the first exchange. Then we have ...
L -20n +50n = T -50n +20n . . . . after the first exchange, each has the same
After the second exchange, amounts trade places:
(L +30n) +6(50) = T
Substituting this into the first equation, we get ...
L +30n = ((L +30n) +300) -30n
30n = 300
n = 10
Leo gave Theo ten $20 bills.
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<em>Comment on the amounts</em>
Theo started with $600 more than Leo, including exactly 16 $50 bills. Leo had at least 10 $20 bills, so he could make the initial exchange. Whatever initial amount Leo had in excess of that $200 was matched in Theo's initial amount, but Theo must have had that excess in $20 bills only. For example, Leo may have started with $300 as 10×$20 +2×$50, but Theo's initial $900 would need to be 5×$20 +16×$50.
