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aivan3 [116]
3 years ago
13

Task location is less important than the task language. T or F

Computers and Technology
1 answer:
Arlecino [84]3 years ago
8 0
I really think its false because of the task  language you need to know
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CHALLENGE ACTIVITY |
fredd [130]

Answer:

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);  

The maxSum is a double type variable which is assigned the maximum of the two variables numA numB PLUS the maximum of the two variables numY numZ using FindMax function. The FindMax() method is called twice in this statement one time to find the maximum of numA and numB and one time to find the maximum of numY numZ. When the FindMax() method is called by passing numA and numB as parameters to this method, then method finds if the value of numA is greater than that of numB or vice versa. When the FindMax() method is called by passing numY and numZ as parameters to this method, then method finds if the value of numY is greater than that of numZ or vice versa. The PLUS sign between the two method calls means that the resultant values returned by the FindMax() for both the calls are added and the result of addition is assigned to maxSum.

Explanation:

This is where the statement will fit in the program.

#include <iostream>

using namespace std;

double FindMax(double num1, double num2) {

  double maxVal = 0.0;    

  if (num1 > num2) { // if num1 is greater than num2,

     maxVal = num1;  // then num1 is the maxVal.    }

  else {          

     maxVal = num2;  // num2 is the maxVal.   }

  return maxVal; }  

int main() {

  double numA;

  double numB;

  double numY;

  double numZ;

  double maxSum = 0.0;  

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);  

  cout << "maxSum is: " << maxSum << endl;   }

Lets take an example to explain this. Lets assign values to the variables.

numA = 6.0

numB = 3.0

numY = 4.0

numZ = 9.0

maxSum =0.0

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);  

FindMax(numA,numB) method call checks if numA>numB or numB>numA and returns the maximum of the two. Here numA>numB because 6.0 is greater than 3.0. So the method returns numA i.e. 6.0

FindMax(numY, numZ) method call checks if numY>numZ or numZ>numY and returns the maximum of the two. Here numZ>numY because 9.0 is greater than 4.0. So the method returns numZ i.e. 9.0

FindMax(numA, numB) + FindMax(numY, numZ) this adds the two values returned by the method FindMax for each call.

FindMax returned maxVal from numA and numB values which is numA i.e. 6.0.

FindMax returned maxVal from numY and numZ values which is numZ i.e. 9.0.

Adding these two values 9.0 + 6.0 = 15

So the complete statement  FindMax(numA, numB) + FindMax(numY, numZ) gives 15.0  as a result.

This result is assigned to maxSum. Hence

maxSum = 15

To see the output on the screen you can use the print statement as:

cout<<maxSum;

This will display 15

6 0
3 years ago
What is star topology
Alexxx [7]
Every node connects to a central network device. like a hub, switch, or computer.
4 0
3 years ago
Read 2 more answers
Flesh out the body of the print_seconds function so that it prints the total amount of seconds given the hours, minutes, and sec
fiasKO [112]

Answer:

Step by step explanation along with code and output is provided below

Explanation:

#include<iostream>

using namespace std;

// print_seconds function that takes three input arguments hours, mints, and seconds. There are 60*60=3600 seconds in one hour and 60 seconds in a minute. Total seconds will be addition of these three  

void print_seconds(int hours, int mints, int seconds)

{

   int total_seconds= hours*3600 + mints*60 + seconds;

   cout<<"Total seconds are: "<<total_seconds<<endl;

}

// test code

// user inputs hours, minutes and seconds and can also leave any of them by  entering 0 that will not effect the program. Then function print_seconds is called to calculate and print the total seconds.

int main()

{

   int h,m,s;

   cout<<"enter hours if any or enter 0"<<endl;

   cin>>h;

   cout<<"enter mints if any or enter 0"<<endl;

   cin>>m;

   cout<<"enter seconds if any or enter 0"<<endl;

   cin>>s;

   print_seconds(h,m,s);

  return 0;

}

Output:

enter hours if any or enter 0

2

enter mints if any or enter 0

25

enter seconds if any or enter 0

10

Total seconds are: 8710

8 0
3 years ago
What would happen if computers only had input peripherals and a CPU?
lisov135 [29]
Then there would be no way to see the output based off what you input. =)
3 0
3 years ago
Does anybody play nitro type
vlabodo [156]

Answer: Nah

Explanation: it kinda sucks and is a waste of time, play better games lol

3 0
3 years ago
Read 2 more answers
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