Answer:
2·(a^2 + b^2) = (a + b)^2
2·a^2 + 2·b^2 = a^2 + 2·a·b + b^2
a^2 + b^2 = 2·a·b
a^2 - 2·a·b + b^2 = 0
(a - b)^2 = 0
a = b
Answer:
49m/s
59.07 m/s
Step-by-step explanation:
Given that :
Distance (s) = 178 m
Acceleration due to gravity (a) = g(downward) = 9.8m/s²
Velocity (V) after 5 seconds ;
The initial velocity (u) = 0
Using the relation :
v = u + at
Where ; t = Time = 5 seconds ; a = 9.8m/s²
v = 0 + 9.8(5)
v = 0 + 49
V = 49 m/s
Hence, velocity after 5 seconds = 49m/s
b) How fast is the ball traveling when it hits the ground?
V² = u² + 2as
Where s = height = 178m
V² = 0 + 2(9.8)(178)
V² = 0 + 3488.8
V² = 3488.8
V = √3488.8
V = 59.07 m/s
Answer:
x ≥12
Step-by-step explanation:
-3x ≤ -36
Divide each side by -3, remembering to flip the inequality
-3x/-3 ≥ -36/-3
x ≥12
Answer:81030m
Step-by-step explanation:1km=1000m, 81km=81000+30=81030m
