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abruzzese [7]
4 years ago
5

Hit or miss (giving away all points for this one)

Mathematics
2 answers:
Leto [7]4 years ago
3 0

Answer:

guess they never miss HUHHHH

Step-by-step explanation:

:))

avanturin [10]4 years ago
3 0

Answer:

l guess they never miss uh.

good day and be safe

∵∴∵∴∵∴∵∴∵      

⊕ΘΞΠΤ⊕      

∵∴∵∴∵∴∵∴∵

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How to solve 3n+9=7n-15
Wewaii [24]
<span>Simplifying 3n + 9 = 7n + -15
9 + 3n = 7n + -15
9 + 3n = -15 + 7n
9 + 3n = -15 + 7n

9 + 3n + -7n = -15 + 7n + -7n
3n + -7n = -4n 9 + -4n = -15 + 7n + -7n
7n + -7n = 0 9 + -4n = -15 + 0 9 + -4n = -15
9 + -9 + -4n = -15 + -9
9 + -9 = 0 0 + -4n = -15 + -9 -4n = -15 + -9
-15 + -9 = -24 -4n = -24
Divide each side by -4
n = 6 </span>
8 0
4 years ago
Read 2 more answers
Please answer and fast​
r-ruslan [8.4K]

Answer:

D

Step-by-step explanation:

3 0
3 years ago
What is the common factors of 12 and 42 also 63 and 84
kaheart [24]
12|2 \\ 6 \ |2 \\ 3 \ |3 \\ 1 \\\\12=2^2*3 \\\\ 42|2\\21|3\\7\ |7\\1 \\\\42=2*3*7 \\\\ G.C.F(12;42)=2*3=6 \\\\\\\ 63|3 \\ 21|3 \\ 7 \ |7 \\ 1 \\\\ 63=3^2*7 \\\\ 84|2 \\ 42|2 \\ 21|3 \\ 7 \ |7 \\ 1 \\\\ 84=2^2*3*7 \\\\ G.C.F(63;84)=3*7=21
3 0
3 years ago
Write the coordinate point for the vertex of this parabola x^2=12y
sergeinik [125]

Answer:

(0,0)

Step-by-step explanation:

the x coordinate for the vertex is at the line of symmetry

ax^2 +bx+c

the line of symmetry is at h =-b/2a

x^2 =12y

divide by 12

1/12 x^2 = y

a = 1/12  b=0 c=0

h = 0/(2* 1/12)

h =0

to find the y coordinate, substitute x=0 back in

y = 1/12 * 0 =  0

the vertex is (0,0)

5 0
3 years ago
In right triangle DEF, it is known that Cos D = (12/13) and Cos F = (5/13). If FD = 39, then DE = ? Hint, draw the right triangl
AnnyKZ [126]

Answer:

The value of the line segment ED is 36.

Step-by-step explanation:

The hypotenuse represents the longest side in the right triangle. In this case, FD represents the hypotenuse as it is a multiple of 13. Based on the trigonometric relations described in the statements, we get the following relationships by definition of cosines:

\cos D = \frac{ED}{FD} (1)

\cos F = \frac{EF}{FD} (2)

If we know that \cos D = \frac{12}{13} and FD = 39, then the length of the line segment ED is:

ED = FD\cdot \cos D

ED = 39\cdot \left(\frac{12}{13} \right)

ED = 36

The value of the line segment ED is 36.

7 0
3 years ago
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