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Nat2105 [25]
3 years ago
6

Explain how the value of the 7 in 327 ,902 will change if you move it to the 1ens place

Mathematics
1 answer:
Greeley [361]3 years ago
5 0
If you move it to the tens place it will wind up being 372,902
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Kyle mixes 45 grams of popcorn with 15 grams of powdered cheese. How much popcorn does Kylebuse per gram of cheese?
nekit [7.7K]

Answer:

B

Step-by-step explanation:

45 grams of popcorn/15 grams of cheese = 3 grams of popcorn per 1 gram of cheese

7 0
3 years ago
Cindi deposited $300 at 7.5% simple interest rate. How much interest will she earn after 5 years?
pav-90 [236]

Answer:

$431

Step-by-step explanation:

using the formula P(1+r/100)^n,

we can substitute the P with $300,

substitute the r with 7.5%,

and substitute the n with 5.

8 0
3 years ago
Muriel says she has written a system of two linear equations that has an infinite number of solutions. One of the equations of t
JulijaS [17]
A system of equations with infinitely many solutions is a system where the two equations are identical. The lines coincide. Anything that is equal to 3y=2x-9 will work. You could try multiply the entire equation by some number, or moving terms around, or adding terms to both sides, or any combination of operations that you apply to the entire equation.

You could multiply the whole thing by 4.5 to get 13.5y=9x-40.5. If you want, you could mix things up and write it in slope-intercept form: y= \frac{2}{3}x-3. The point is, anything that is equivalent to the original equation will give infinitely many solutions x and y. You can test this by plugging in values x and y and seeing the answers! 

The attached graph shows that four different equations are really the same.

7 0
3 years ago
Read 2 more answers
Find the domain of the function y = 3 tan(23x)
solmaris [256]

Answer:

\mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

In other words, the x in f(x) = 3\, \tan(23\, x) could be any real number as long as x \ne \displaystyle \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right) for all integer k (including negative integers.)

Step-by-step explanation:

The tangent function y = \tan(x) has a real value for real inputs x as long as the input x \ne \displaystyle k\, \pi + \frac{\pi}{2} for all integer k.

Hence, the domain of the original tangent function is \mathbb{R} \backslash \displaystyle \left\lbrace \left. \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

On the other hand, in the function f(x) = 3\, \tan(23\, x), the input to the tangent function is replaced with (23\, x).

The transformed tangent function \tan(23\, x) would have a real value as long as its input (23\, x) ensures that 23\, x\ne \displaystyle k\, \pi + \frac{\pi}{2} for all integer k.

In other words, \tan(23\, x) would have a real value as long as x\ne \displaystyle \frac{1}{23} \, \left(k\, \pi + \frac{\pi}{2}\right).

Accordingly, the domain of f(x) = 3\, \tan(23\, x) would be \mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

4 0
2 years ago
Solve for j. 144j2 + 21 = 85
Sphinxa [80]

Answer:

2/3

Step-by-step explanation:

I assume the 2 after the j is a square. So, we bring the 21 to the other side by subtracting it from both sides, getting 144j^2=64. Now we divide to get 64/144 = j^2. Make sure NOT to simplify it, it's perfect right now. The square root of that is \sqrt{64}/ \sqrt{144}, or 8/12, which we can now simplify to 2/3. Hope this helps!

5 0
3 years ago
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