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luda_lava [24]
3 years ago
15

Plz help me. how many solutions

Mathematics
2 answers:
Bas_tet [7]3 years ago
8 0

Answer:

no solutions

Step-by-step explanation:

2y = 4x+6

y = 2x+6

Divide the first equation by 2

y = 2x+3

These are parallel lines ( same slope) but different y intercepts

They will never intersect, so they have no solutions

tresset_1 [31]3 years ago
4 0

Answer:

B   No solutions

Step-by-step explanation:

2y = 4x + 6       first equatión

 y  = 2x + 6       second equation

from the first equation

y = (4x+6)/2

y = 4x/2 + 6/2

y = 2x + 3       third equation

matching second equatión and third equation

2x + 6 = 2x + 3

2x - 2x = 3 - 6

0 ≠ -3

then:

Β  No solutions

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The equation is f(x) = 4x^2 - 4.

You can find this by using an equation with parenthesis that equal each of the zeros.

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Now, this equation will not give us the vertex that we're looking for. So, we must add a constant being multiplied to the front of it.

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Now we can find the constant by putting our vertex into the equation and solving.

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3 years ago
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Answer:

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5 0
4 years ago
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BaLLatris [955]

Answer:

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AysviL [449]
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