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3 years ago

What’s the vertex of this equation?

Mathematics

1 answer:

statuscvo [17]3 years ago

3 0

f (x) = a(x - h)^2 + k, where (h, k) is the vertex of the parabola.

Do you see the h and k in your equation?

-h = -(-2) = 2

We see that k = -4.

Our vertex is (2, -4).

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F(x) = - 2x<br> g(x) = 8x^2– 5x+7<br> Find (f .g)(x).

N76 [4]

Answer:

$\large\boxed{(f\cdot g)(x)=-16x^3+10x^2-14x}$

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$f(x)=-2x\\\\g(x)=8x^2-5x+7\\\\(f\cdot g)(x)=f(x)\cdot g(x)\\\\\text{substitute:}\\\\(f\cdot g)(x)=(-2x)(8x^2-5x+7)\qquad\text{use the distributive property}\\\\(f\cdot g)(x)=(-2x)(8x^2)+(-2x)(-5x)+(-2x)(7)\\\\(f\cdot g)(x)=-16x^3+10x^2-14x$

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4 years ago

Type the correct answer in the box.

lana [24]

Correct question is;

Type the correct answer in the box bellow: If cos x = sin(20 + x)° and 0° < x < 90°, the value of x is ...........

Answer:

x = 35°

Step-by-step explanation:

We are told that;

cos x = sin(20 + x)°

and 0° < x < 90°

From trigonometric identities, we know that;

cos x = sin (90 - x)

Applying to our question gives;

sin (90 - x) = sin (20 + x)°

Comparing both sides, we have;

90 - x = 20 + x

Rearranging;

90 - 20 = x + x

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x = 70/2

x = 35°

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