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kari74 [83]
2 years ago
14

What is this trinomial in factored form? 3a^2-2a-1

Mathematics
1 answer:
Dafna1 [17]2 years ago
4 0
<span>Simplifying 3a2 + -2a + -1 = 0 Reorder the terms: -1 + -2a + 3a2 = 0 Solving -1 + -2a + 3a2 = 0 Solving for variable 'a'. Factor a trinomial. (-1 + -3a)(1 + -1a) = 0 Subproblem 1Set the factor '(-1 + -3a)' equal to zero and attempt to solve: Simplifying -1 + -3a = 0 Solving -1 + -3a = 0 Move all terms containing a to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + -3a = 0 + 1 Combine like terms: -1 + 1 = 0 0 + -3a = 0 + 1 -3a = 0 + 1 Combine like terms: 0 + 1 = 1 -3a = 1 Divide each side by '-3'. a = -0.3333333333 Simplifying a = -0.3333333333 Subproblem 2Set the factor '(1 + -1a)' equal to zero and attempt to solve: Simplifying 1 + -1a = 0 Solving 1 + -1a = 0 Move all terms containing a to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1a = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1a = 0 + -1 -1a = 0 + -1 Combine like terms: 0 + -1 = -1 -1a = -1 Divide each side by '-1'. a = 1 Simplifying a = 1Solutiona = {-0.3333333333, 1}</span>
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Using the binomial distribution, it is found that the mean and the standard deviation of variable x are given as follows:

\mu = 3, \sigma = 0.87

<h3>What is the binomial probability distribution?</h3>

It is the probability of exactly <u>x successes on n repeated trials, with p probability</u> of a success on each trial.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

In this problem, we have that the parameters are given as follows:

n = 4, p = 0.75.

Hence the mean and the standard deviation are given as follows:

  • E(X) = np = 4 x 0.75 = 3.
  • \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{4 \times 0.75 \times 0.25} = 0.87

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

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I will mark you brainliest if your answer is right
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12.72 is the answer
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The table below shows the data for a random sample of fish that were collected from and later released into a lake:
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Step-by-step explanation:

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