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Vinvika [58]
3 years ago
9

Nia is training for a marathon. Her average speed during training so far is 5.8 miles per hour. If she runs at that rate for a t

raining run that is 1 hour and 12 minutes long, how far will Nia run?
A. 4.83 miles

B. 6.96 miles

C. 7.25 miles

D. 4.64 miles
Mathematics
1 answer:
Rudik [331]3 years ago
4 0

Answer:

Step-by-step explanation:

5.8miles an hour = 5.8/60miles per minute = 0.0967miles per minute.

1hr and 12minutes = 72minutes

The total distance covered = 72 * 0.0967 = 6.9624miles

That's approximately 6.96miles or option B.

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Type the correct answer in the box<br> The area of the figure units.
Brrunno [24]

Answer:

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3 years ago
A clothing store is having a sale on holiday socks. Each pair of socks costs x dollars. You leave the store with 6 pairs of sock
ss7ja [257]

Answer: $ 14

Step-by-step explanation:

Since, the cost of 1 pair of socks = x

The cost of 6 pair of socks = 6 x

Total amount spend = $ 40

According to the question,

6 x - 14 = 40

6 x = 40 + 14

6 x  = 54

x = 9

Thus, the original price of one pair of socks = $ 9

⇒ The original price of 6 pairs of socks = $ 54

Hence, the total change = original price of socks - the price of socks in the sale = 54 - 40 =  $ 14

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4 years ago
What is the Range of a degree 2 polynomial with a vertex at (-92801, 7) and a leading coefficient that is negative?
Gennadij [26K]

Answer:

The range is [7, -infinity)

Step-by-step explanation:

Since the leading coefficient is negative and it is a degree 2 polynomial, it is a parabola opened for downwards.

6 0
3 years ago
What is the solution to 10x + 99 = 189
belka [17]
First do 189-99. thats 90. then do 90/10 which is 9
8 0
3 years ago
Read 2 more answers
Let the given rhombus be abcd in which ab = bc = cd = da = 20 cm and
natka813 [3]

Answer:

<u>384 cm²</u>

Step-by-step explanation:

Property of rhombus :

  • Diagonals of rhombus bisect each other and are perpendicular to each other

Given :

  1. Rhombus ABCD and its diagonals AC and BD bisect each other at O
  2. AC ⊥ BD
  3. AB = BC = CD = DA = 20 cm
  4. AC = 24 cm

Solving :

Area of the given rhombus is twice the Area of ΔABC formed by the given diagonal and two adjacent sides.

  • 2 × 1/2 × OB × AC
  • 24 × OB
  • 24 × √AB² - AO²
  • 24 × √20² - (AC/2)²
  • 24 × √400 - 144
  • 24 × √256
  • 24 × 16
  • <u>384 cm²</u>

6 0
2 years ago
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