Question

WILL GIVE BRAINLIEST

Answer 1

$\frac{3x^3+9x^2-6x}{-3x}$
Since the denominator is a monomial, we divide each term of the trinomial in the numerator by the denominator.
$\frac{3x^3}{-3x} = -1x^2$, because 3/-3 = 1 and x³/x = x².
$\frac{9x^2}{-3x}=-3x$; 9/-3 = -3 and x²/x = x.
$\frac{-6x}{-3x} = 2$; -6/-3 = 2 and x/x = 1, so we have 2*1  = 2.
Together this gives us $-x^2-3x+2$