Second moment of area about an axis along any diameter in the plane of the cross section (i.e. x-x, y-y) is each equal to (1/4)pi r^4.
The second moment of area about the zz-axis (along the axis of the cylinder) is the sum of the two, namely (1/2)pi r^4.

The derivation is by integration of the following:
int int y^2 dA
over the area of the cross section, and can be found in any book on mechanics of materials.

6 0

2 years ago

A park district has 45 pine trees and 30 oak trees to be planted. They are separating the trees for different areas. They want e

Lady_Fox [76]

Answer:

greatest number of areas that can be created=5

Step-by-step explanation:

given data

Number of pine trees = 45

Number of oak trees = 30

solution

we want area have same number of both trees

so we get here greatest number of area

we find here greatest common factor of 45 and 30

so Prime factorization of 45 and 30 are

45 = 3 × 3 × 5

30 = 2 × 3 × 5

as here GCF = 5

so here greatest number of areas that can be created=5

6 0

2 years ago