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Temka [501]
3 years ago
13

Andrea enjoys running. She keeps a daily journal to record how far she runs. She wears a pedometer to calculate the exact distan

ce in kilometers.
Monday 3.6
Tuesday 4.705
Wednesday 5.92
What is the total distance, in kilometers, that Andrea ran over the three days?
Mathematics
2 answers:
Lana71 [14]3 years ago
5 0

Again this is a simple addition problem I think.

Add 3.6+4.705+5.92=

14.225 kilometers that Andrea ran over the three days.

Hope this helps, have a good day. c;

Akimi4 [234]3 years ago
3 0

Answer:

14.225

Step-by-step explanation:

It is a simple addition problem, just the decimal points are confusing.

Add 3.6+4.705+5.92= 14.225!

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Answer:

n = 2

Step-by-step explanation:

1.2n - 1.5 = 0.45n

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3 years ago
Help me out PLEASE. begging.
spayn [35]
The ladder will reach 122 ft up the building.

The 120 feet of the extended ladder, since it will be leaning against the building, will be the hypotenuse of the right triangle.  x will be the height from the top of the fire truck to the point where the ladder hits the building.  75° is the angle the ladder will make with the fire truck. 

We have an angle, the side opposite the angle, and the hypotenuse.  Opposite/hypotenuse is the ratio for sine, so we set up our equation as such:

x/120 = sin 75

Multiply both sides by 120:
120(x/120) = 120*sin 75
x = 120*sin 75
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3 years ago
Find the greatest common factor of the following monomials: 20a3 and 8a2
dimulka [17.4K]

GCF of given monomials are 4a^2

<em><u>Solution:</u></em>

<em><u>Given that we have to find the greatest common factor</u></em>

Given monomials are:

20a^3 \text{ and } 8a^2

When we find all the factors of two or more numbers, and some factors are the same, then the largest of those common factors is the Greatest Common Factor

Let us first find the GCF of 20 and 8 and then find GCF of variables and then multiply them together

<em><u>GCF of 20 and 8:</u></em>

The factors of 8 are: 1, 2, 4, 8

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Then the greatest common factor is 4

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Thus GCF is a^2

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Thus GCF of given monomials are 4a^2

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let me know if you need explanations/more help

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