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Alekssandra [29.7K]
3 years ago
14

Help asap , apx algebra 1

Mathematics
1 answer:
Troyanec [42]3 years ago
5 0
D. 3
F(x) is referring to y. The question is asking what x is when y is 4.
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What does the constant term in the numerator represent?
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College freshmen took a psychology exam. If the mean is 80, the SD is 10, and the scores have normal distribution, what percent
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  (a)  2%

Step-by-step explanation:

A score of 60 is 2 standard deviations below the mean (80 -2·10 = 60). The empirical rule tells you that 95% of the distribution is within 2 standard deviations of the mean. The remaining 5% is split evenly between those that are more than 2 SD above the mean and those that are more than 2 SD below the mean.

That tells you the percentage who failed is about 2.5%. The best answer choice is 2%.

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<em>Additional comment</em>

The empirical rule is a little bit sloppy, but it gets you in the ballpark. The actual percentage is closer to 2.275%.

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3 years ago
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1. The table shows the probabilities of a response chocolate or vanilla when asking a child or adult. Use the formula for condit
Stels [109]
\begin{matrix}&\text{chocolate}&\text{vanilla}&\text{total}\\\text{children}&0.14&0.26&0.40\\\text{adults}&0.21&0.39&0.60\\\text{total}&0.35&0.65&1.00\end{matrix}

a. "Chocolate" and "Adults" (whatever those mean) will be independent as long as

P(\text{chocolate}\cap\text{adults})=P(\text{chocolate})\cdot P(\text{adults})

"Chocolate" has the marginal distribution given by the second column, with a total probability of P(\text{chocolate})=0.35. Similarly, "Adults" has the marginal distribution described by the third row, so that P(\text{adults})=0.60. Then

P(\text{chocolate})\cdot P(\text{adults})=0.35\cdot0.60=0.21

Meanwhile, the joint probability of "Chocolate" and "Adults" is given by the cell in the corresponding row/column, with P(\text{chocolate}\cap\text{adults})=0.21.

The probabilities match, so these events are indeed independent.

Parts (b) and (c) are checked similarly.

b. Yes;


P(\text{children})\cdot P(\text{chocolate})=0.40\cdot0.35=0.14
P(\text{children}\cap\text{chocolate})=0.14

c. Yes;

P(\text{vanilla})\cdot P(\text{children})=0.65\cdot0.40=0.26
P(\text{vanilla}\cap\text{children})=0.26
5 0
3 years ago
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