By using the rules that the value inside square root can’t be negative and the denominator value can’t be zero, the domain for the given function is a) x<-1 and x>1 b) p≤1/2 c) s>-1.
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Write the restrictions that should be imposed on the variable for each of the following function. Then find, explicitly, the domain for each function and write it in the interval notation a) f(x)=(x-2)/(x-1) b) g(p)=√(1-2p) c) m(s)= (s^2+4s+4)/√(s+1)
Ans. We know that a number is not divisible by zero and number inside a square root can not be negative. In both the cases the outcome will be imaginary.
a) For this case the denominator x-1 can not be zero. So, x ≠1 and the domain is x<-1 and x>1.
b) For this case the value inside square root can’t be negative. So, p can’t be greater than 1/2 the domain is p≤1/2.
c) For this case also the value inside square root can’t be negative and the denominator value can’t be zero. So, s can’t equal or less than -1 and domain is s>-1.
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Answer:
Mike can go 124 miles
Step-by-step explanation:
Car rent = $29.20
However, a customer has to pay $0.20 for every mile.
Mike has $54 to spend on the car for a day.
If he pays the car rent which is $29.20, then he has
$54 - $29.20 = $24.80 remaining
1 mile = $0.20
x miles = $24.80
By cross multiplication
0.20x = 1 * 24.80
x = 24.80/0.20
x = 124 miles
Ty=x 9
Malcolm=x+2 11
fred=2x+4 22
x+x+2+2x+4=42
4x+6=42
-6 -6
4x=36
36÷4
x=9
The reciprocal of a fraction is only a whole number when
the numerator of the original fraction is ' 1 ' or a factor of
the denominator (original fraction is not in simplest form).
Any other time, the reciprocal of the fraction is another fraction.
(It'll be an improper fraction, and can be written as a mixed number.)
The reciprocal of a fraction is just the same fraction
turned upside down.
-- The reciprocal of 1/5 is 5/1 or just 5 .
(Original numerator is ' 1 '.)
-- The reciprocal of 5/25 is 25/5 or just 5 .
(Original fraction is not in simplest form.)
-- The reciprocal of 5/7 is 7/5 , or 1 and 2/5 .