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yanalaym [24]
3 years ago
15

A cell phone plan charges $59.90 a month, plus $0.25 per text message. Which inequality can be

Mathematics
2 answers:
Licemer1 [7]3 years ago
5 0
$59.90+ $0.25x
This is because $59.90 is the amount you already have to pay so you would do $0.25x to get the number of texts you could send.
gtnhenbr [62]3 years ago
3 0

Answer:

75>59.90+0.25x

Step-by-step explanation:

if you want the answer it's 59=the number of texts you can send

59.90 because its the amount you already have to pay

0.25x because you'll have to pay 0.25 for every text you send.

The less than sign because it has to be less than 75

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serg [7]
The answer should be hid
6 0
3 years ago
What is the value of x?
djverab [1.8K]

Answer:

x = 55°

Step-by-step explanation:

Hello!

The sum of angles in a triangle is 180°.

To solve for x, we have to subtract the given angles from 180°.

<h3>Solve for x</h3>
  • 180° = ∠1 + ∠2 + ∠x
  • 180° = 75° + 50° + x°
  • 180° - 75° - 50° = x°
  • 55° = x°

The value of x is 55°.

6 0
2 years ago
Read 2 more answers
How long will it take a person to double $2000 at a 6% interest rate, compounded annually?
aleksandr82 [10.1K]
Well you would do 6% times 2000 (.06 *2000) 120

5 0
3 years ago
In a football or soccer game, you have 22 players, from both teams, in the field. what is the probability of having at least any
Tamiku [17]

We can solve this problem using complementary events. Two events are said to be complementary if one negates the other, i.e. E and F are complementary if

E \cap F = \emptyset,\quad E \cup F = \Omega

where \Omega is the whole sample space.

This implies that

P(E) + P(F) = P(\Omega)=1 \implies P(E) = 1-P(F)

So, let's compute the probability that all 22 footballer were born on different days.

The first footballer can be born on any day, since we have no restrictions so far. Since we're using numbers from 1 to 365 to represent days, let's say that the first footballer was born on the day d_1.

The second footballer can be born on any other day, so he has 364 possible birthdays:

d_2 \in \{1,2,3,\ldots 365\} \setminus \{d_1\}

the probability for the first two footballers to be born on two different days is thus

1 \cdot \dfrac{364}{365} = \dfrac{364}{365}

Similarly, the third footballer can be born on any day, except d_1 and d_2:

d_3 \in \{1,2,3,\ldots 365\} \setminus \{d_1,d_2\}

so, the probability for the first three footballers to be born on three different days is

1 \cdot \dfrac{364}{365} \cdot \dfrac{363}{365}

And so on. With each new footballer we include, we have less and less options out of the 365 days, since more and more days will be already occupied by another footballer, and we can't have two players born on the same day.

The probability of all 22 footballers being born on 22 different days is thus

\dfrac{364\cdot 363 \cdot \ldots \cdot (365-21)}{365^{21}}

So, the probability that at least two footballers are born on the same day is

1-\dfrac{364\cdot 363 \cdot \ldots \cdot (365-21)}{365^{21}}

since the two events are complementary.

8 0
3 years ago
I need helpppppp i have no idea what im looking at lol
Fed [463]

The correct answer is option B which is  Cot\theta=\dfrac{24}{7}.

<h3>What is trigonometry?</h3>

Trigonometry is the branch of mathematics which set up a relationship between the sides and angle of the right-angle triangles.

Given that:-

Sec\theta=\dfrac{25}{24}

The value of cot theta will be calculated as:-

We know that sec theta is the ratio of hypotenuse and base and cot theta is the ratio of base and perpendicular so we will find the value of perpendicular by applying the Pythagorean theorem.

H² = P²  +  B²
P² = H²  -  B²

P²  =  25²  -  24 ²  = 49

P  = √49 =  7

Now the value of cot theta will be calculated as:-

Cot\theta =\dfrac{B}{P}=\dfrac{24}{7}

Therefore the correct answer is option B which is  Cot\theta=\dfrac{24}{7}.

To know more about Trigonometry follow

brainly.com/question/24349828

#SPJ1

5 0
2 years ago
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