Answer:
Step-by-step explanation:
(x^2+y^2)^2=(x^2)^2+2x^2y^2+(y^2)^2
Adding and substracting 2x^2y^2
We get
(x^2+y^2)^2=(x^2)^2+2x^2y^2+(y^2)^2 +2x^2y^2-2x^2y^2
And we know a^2-2ab+b^2=(a-b)^2
So we identify (x^2)^2 as a^2 ,(y^2)^2 as b^2 and -2x^2y^2 as - 2ab. So we can rewrite (x^2+y^2)^2=(x^2 - y^2)^2 + 2x^2y^2 + 2x^2y^2= (x^2 - y^2)^2+4x^2y^2= (x^2 - y^2)^2+2^2x^2y^2
Moreever we know (a·b·c)^2=a^2·b^2·c^2 than means 2^2x^2y^2=(2x·y)^2
And (x^2+y^2)^2=(x^2 - y^2)^2 + (2x·y)^2
Answer:
Option C, both functions have an y-intersect equal to 2.
Step-by-step explanation:
When we have a function f(x), the y-intercept is the value f(0). This is the point where the graph of the function intersects the y-axis.
Then, for f(x) = -x^2 + 5*x + 2
The y-intercept is:
f(0) = -0^2 + 5*0 + 2 = 2
f(0) = 2
And for g(x) we do not have the equation, but we have the graph, so we can just look at which value of y does the graph intersects the y-axis.
We can see that the graph intersects the graph at y = 2
Then the y-intersect is: g(0) = 2
So both functions have the same y-intersect. Then the correct option is C.
Answer:
add 2 zeros at the end of all of them
Step-by-step explanation:
Answer:
It’s graph B
Step-by-step explanation:
If you look at graph A, the y intercept will be at -3 instead of a negative 5.
Good luck!
