Answer:
Option D is correct option.
<u>Short call and long put</u>
Explanation:
Short call and long put = - max (S - K, 0) + max (K - S, 0);
As S declines, the payoff from long put position improves. As S increases, payoff from short call position loses money. This option satisfies the condition put in the question.
The indication for where the fact came from is called citation
Answer:
3 years
Explanation:
The computation of the time period is shown below
Present value of annuity = Annuity × [1 - (1 + interest rate)^-time period] ÷ rate
$2,000 = $734.42 × [1 - (1.05)^-n] ÷ 0.05
$2,000 = $14,688.4 × [1-(1.05)^-n]
1-(1.05)^-n = ($2000 ÷ $14,688.4)
(1.05)^-n = 1 - ($2000 ÷ $14,688.4)
( 1 ÷ 1.05)^n = 0.86383813
Now take the log to the both sides
n × log(1 ÷ 1.05) = log0.86383813
n = log0.86383813 ÷ log (1 ÷ 1.05)
= 3 years
Answer:
166.25 hours
Explanation:
It take 25 hours if the production is going at 100% capacity, but the production is only going at 67%, therefore, 33% of the capacity is under utilized. It takes 8.25 more hours to finish the unit since the capacity is only at 67%. Finally, it takes 25+8.25 hours to finish a single product, hence taking 166.25 hours for 5 units.
We do this like this:
--> 25 ------ 100
--> X ------ 33
--> 33*25 = 100*X
--> 825/100
--> X=8.25
Hope this clears everything. Thankyou.
