Question

Does anyone know how to solve this ?

Answer 1

SinB=AC/AB=14/50=7/25
tanB=AC/BC=14/48=7/24

Answer 2

Answer: The exact values of indicated trigonometric functions are:

$\sin B=\frac{7}{25}\\\\and,\\\\\tan B=\frac{7}{24}$

Step-by-step explanation:

Since we have given that

ACB is a right angled triangle,

AC = 14 units

CB = 48 units

BA = 50 units

For sin B ,we will use "SOH" :

$\sin B=\frac{AC}{AB}\\\\\sin B=\frac{14}{50}\\\\\sin B=\frac{7}{25}$

similarly,

For tan B, we will use "TOH" :

$\tan B=\frac{Perpendicular}{Hypotenuse}=\frac{AC}{CB}\\\\\tan B=\frac{14}{48}\\\\\tan B=\frac{7}{24}$

Hence, The exact values of indicated trigonometric functions are:

$\sin B=\frac{7}{25}\\\\and,\\\\\tan B=\frac{7}{24}$