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3 years ago

WILL MARK BRAINLIEST

Mathematics

2 answers:

lilavasa [31]3 years ago

6 0

The correct answer is 30 because for every 3 on width you add 5 on length

Komok [63]3 years ago

5 0

The correct answer is 30.
You must follow the pattern that is given.

The width as you can see, goes up by 3 every step.
The length goes up by 5 every step.
So, if the calculations are correct and the pattern is followed:

Width:
3
6
9
12
15
18

Length:
5
10
15
20
25
30

The 6th term of the width is 18 so the 6th term for the length is 30.

Hope that helps!!

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leva [86]

In order to simplify, let's add 6x and 13x.

We will get 19x, and that is the answer!

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4 years ago

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In roulette, you may bet whether the number that comes up is odd (or even). (Remember that 0 and 00 do not count as either odd o

EastWind [94]

Answer: - 0.027

Step-by-step explanation:

Win = any even number between (0 - 36)

Therefore,

Lose = any odd number between 0 —36 including 0

Assume Bet amount = $1

Expected value is calculate by summing all possible outcomes by their respective probabilities.

Expected value = [(p(winning) × net win value) + (p(losing +net loss value]

P(winning) = p(even) = 18/37

P(losing) = p(odd) +p(0) = 19/37

Net win value = $2

Net loss value = $-1

Expected value = [(18/37) × ($1) + (19/37) × (-$1)]

Expected value = 0.48648648 - 0.51351351

Expected value = - 0.027

7 0

3 years ago

Suppose a consumer group suspects that the proportion of households that have three cell phones NOT known to be 30%. A cell phon

leva [86]

Answer:

We conclude that the actual percentage of households is equal to 30%.

Step-by-step explanation:

We are given that a consumer group suspects that the proportion of households that have three cell phones NOT known to be 30%.

Their marketing people survey 150 households with the result that 43 of the households have three cell phones.

Let p = proportion of households that have three cell phones NOT known.

So, Null Hypothesis, $H_0$ : p = 30% {means that the actual percentage of households is equal to 30%}

Alternate Hypothesis, $H_A$ : p $\neq$ 30% {means that the actual percentage of households different from 30%}

The test statistics that would be used here One-sample z-test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of households having three cell phones = $\frac{43}{150}$ = 0.29

n = sample of households = 150

So, the test statistics = $\frac{0.29-0.30}{\sqrt{\frac{0.30(1-0.30)}{150} } }$

= -0.27

The value of z test statistic is -0.27.

Also, P-value of the test statistics is given by;

P-value = P(Z < -0.27) = 1 - P(Z $\leq$ 0.27)

= 1 - 0.6064 = 0.3936

Now, at 1% significance level the z table gives critical value of -2.58 and 2.58 for two-tailed test.

Since our test statistic lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the actual percentage of households is equal to 30%.

4 0

3 years ago