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VashaNatasha [74]
3 years ago
6

How many sixths are there in 6 1/3

Mathematics
2 answers:
trasher [3.6K]3 years ago
7 0
1/3=2/6 so
6=36/6 and you add 2/6 and 36/6 to get 38/6 or 19/3
Or 38 sixths
Anni [7]3 years ago
7 0

Answer:


Step-by-step explanation:112 seats and we know 70 are seated.

112-70=42

Now 42 seats are available and there are 7 seats in each row.

42÷7=6

So the answer is 6 rows available



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A fair coin is tossed 20 times. The probability of getting the three or more heads in a row is 0.7870 and the probability of get
adelina 88 [10]

Answer:

The  value is  P( H \  n \  T ) =  0.6049

Step-by-step explanation:

From the question we are told that

   The  number of times  is  n  =  20  

   The probability of getting three or more heads in a row is  P(H) =  0.7870

   The probability of getting three or more heads in a row or three or more tails in a row is    P(H \ u \   T )  =  0.9791

Generally given that it is a fair coin , then   P(H) = P(T) =  0.7870

Here  P(T) is  probability of getting three or more tails  in a row

Generally  the probability of getting three or more heads in a row and three or more tails in a row is mathematically represented as

        P( H \  n \  T ) =  P(H) + P(T) -  P( H \  u \  T )

=>   P( H \  n \  T ) =  0.7870  + 0.7870 -  0.9791

=>   P( H \  n \  T ) =  0.6049

 

7 0
3 years ago
What is the general equation of a cosine function with an amplitude of 3, a period of 4 pi, and a horizontal shift of negative p
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<h3>How to get the cosine function?</h3>

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Where A is the amplitude and p is the phase, then we know that:

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brainly.com/question/4372174

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Komok [63]

Answer:

4.4%

Step-by-step explanation:

A=P\left(1+\frac{r}{n}\right)^{nt}

A=P(1+  

n

r

​  

)  

nt

 

Compound interest formula

A=11700\hspace{35px}P=6900\hspace{35px}t=12\hspace{35px}n=365

A=11700P=6900t=12n=365

Given values

11700=

11700=

\,\,6900\left(1+\frac{r}{365}\right)^{365(12)}

6900(1+  

365

r

​  

)  

365(12)

 

Plug in values

11700=

11700=

\,\,6900\left(1+\frac{r}{365}\right)^{4380}

6900(1+  

365

r

​  

)  

4380

 

Multiply

\frac{11700}{6900}=

6900

11700

​  

=

\,\,\frac{6900\left(1+\frac{r}{365}\right)^{4380}}{6900}

6900

6900(1+  

365

r

​  

)  

4380

 

​  

 

Divide by 6900

1.695652174=

1.695652174=

\,\,\left(1+\frac{r}{365}\right)^{4380}

(1+  

365

r

​  

)  

4380

 

\left(1.695652174\right)^{1/4380}=

(1.695652174)  

1/4380

=

\,\,\left[\left(1+\frac{r}{365}\right)^{4380}\right]^{1/4380}

[(1+  

365

r

​  

)  

4380

]  

1/4380

 

Raise both sides to 1/4380 power

1.000120571=

1.000120571=

\,\,1+\frac{r}{365}

1+  

365

r

​  

 

-1\phantom{=}

−1=

\,\,-1

−1

Subtract 1

0.000120571=

0.000120571=

\,\,\frac{r}{365}

365

r

​  

 

365\left(0.0001206\right)=

365(0.0001206)=

\,\,\left(\frac{r}{365}\right)365

(  

365

r

​  

)365

Multiply by 365

0.044008415=

0.044008415=

\,\,r

r

4.4008415\%=

4.4008415%=

\,\,r

r

7 0
3 years ago
Read 2 more answers
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