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3 years ago

Find the solution set for the given inequality if the set for x is the set {1, 2, 3, 4}.

Mathematics

2 answers:

expeople1 [14]3 years ago

6 0

$4x-3\geq5\\
4x\geq8\\
x\geq2$
So, it's B.

Dima020 [189]3 years ago

4 0

$4x-3\geq5\ \ \ |+3\\\\4x\geq8\ \ \ |:4\\\\x\geq2\\\\Answer:\\the\ set\ B.\\\\2\geq2\\3\geq2\\4\geq2$

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Help, please. I just need an answer, so if anyone is bored, for the love of god please...

Alla [95]

Answer:B & E

Step-by-step explanation:

We can first rearrange the function to isolate y. Then, we can find the slope as the function is in the form y=mx+b.

$3x-4y=7\\-4y=-3x+7\\y=\frac{3}{4}x-\frac{7}{4}$

Since parallel lines have the same slope, we can put the slope of 3/4 into the point slope form to get the answer.

<em>For reference, the point-slope form is </em> $y-y_1=m(x-x_1)$

$y+2=\frac{3}{4}(x+4)\\y+2=\frac{3}{4}x+3\\y=\frac{3}{4}x+1$

The first line is found in option E, so option E is one of the correct options.

We can also move the x to the other side, as two of the 5 options have both variables on the left (B and C).

$-\frac{3}{4}x+y=1$

If we multiply the whole equation by -4, we can get rid of the fraction.

$-4(-\frac{3}{4}x+y)=-4(1)\\3x-4y=-4$

Hence, option B is also correct.

7 0

1 year ago

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Marina86 [1]

I hope this helps you find the answer you're looking for

8 0

3 years ago

True or false: equilateral triangles can be classified as acute right or obtuse

Ne4ueva [31]

False, since all sides are equal all angles must be equal and when you have an obtuse or right triangle only on angle is obtuse or right. since one is different it cannot be equal on all sides making this statement false

8 0

2 years ago

Consider the sequence of numbers: 3/8, 3/4, 1 /18, 1 1/2, 1 7/8

vredina [299]

Question:

Consider the sequence of numbers: $\frac{3}{8}, \frac{3}{4}, 1\frac{1}{8}, 1\frac{1}{2}, 1\frac{7}{8}$

Which statement is a description of the sequence?

(A) The sequence is recursive, where each term is 1/4 greater than its preceding term.

(B) The sequence is recursive and can be represented by the function

f(n + 1) = f(n) + 3/8 .

(D) The sequence is arithmetic and can be represented by the function

f(n + 1) = f(n)3/8.

Answer:

Option B:

The sequence is recursive and can be represented by the function

$f(n + 1) = f(n) + \frac{3}{8} .$

Explanation:

A sequence of numbers are

$\frac{3}{8}, \frac{3}{4}, 1\frac{1}{8}, 1\frac{1}{2}, 1\frac{7}{8}$

Let us first change mixed fraction into improper fraction.

$\frac{3}{8}, \frac{3}{4}, \frac{9}{8}, \frac{3}{2}, \frac{15}{8}$

To find the pattern of the sequence.

To find the common difference between the sequence of numbers.

$\frac{3}{4}-\frac{3}{8}=\frac{6}{8}-\frac{3}{8}= \frac{3}{8}$

$\frac{9}{8}-\frac{3}{4}=\frac{9}{8}-\frac{6}{8}= \frac{3}{8}$

$\frac{3}{2}-\frac{9}{8}=\frac{12}{8}-\frac{9}{8}= \frac{3}{8}$

$\frac{15}{8}-\frac{3}{2}=\frac{15}{8}-\frac{12}{8}= \frac{3}{8}$

Therefore, the common difference of the sequence is 3.

That means each term is obtained by adding $\frac{3}{8}$ to the previous term.

Hence, the sequence is recursive and can be represented by the function $f(n + 1) = f(n) + \frac{3}{8} .$

3 0

2 years ago

The graph of a proportional relationship passes through the point (6, 21). What is the equation for the relationship?

Kipish [7]

Answer:

The equation for the relationship is $y = \frac{7}{2}\cdot x$ .

Step-by-step explanation:

Given that point $(x,y) = (6, 21)$ is part of a direct relationship. That is:

$y \propto x$

$y = k\cdot x$ (1)

Where $k$ is the proportionality constant.

If we know that $x = 6$ and $y = 21$ , then the proportionality constant is:

$k = \frac{y}{x}$

$k = \frac{21}{6}$

$k = \frac{7}{2}$

Lastly, the equation for the relationship is $y = \frac{7}{2}\cdot x$ .

7 0

2 years ago