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brilliants [131]

3 years ago

15

There are 50 bacteria in a test tube. After one hour, the number of bacteria is 100. After two hours, the number of bacteria is

200. After three hours, the number is 400. Suppose the growth continues at this rate. Which expression shows the number of bacteria after n hours?

2 answers:

r-ruslan [8.4K]3 years ago

7 0

I think its n(50 x 2)

Free_Kalibri [48]3 years ago

3 0

Answer:

n(50 x 2)

Hope this helps!

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Solve by elimination:<br> 2x + 4y = 34<br> x+4y = 27<br> A (7,-5)<br> B (6,6)<br> (7,5)<br> (5,7)

julsineya [31]

Answer:

(7,5)

Step-by-step explanation:

{2x + 4y = 34

{4y = 27 - x

2x + 27 - x = 34

x=7

4y = 27 - 7

y = 5 so the answer is ( 7,5)

3 0

3 years ago

Read 2 more answers

Need brief explanation about why false is correct

anyanavicka [17]

<u>We are given the equation:</u>

(a + b)! = a! + b!

<u>Testing the given equation</u>

In order to test it, we will let: a = 2 and b = 3

So, we can rewrite the equation as:

(2+3)! = 2! + 3!

5! = 2! + 3!

<em>We know that (5! = 120) , (2! = 2) and (3! = 6):</em>

120 = 2 + 6

We can see that LHS ≠ RHS,

So, we can say that the given equation is incorrect

6 0

2 years ago

What are the transformations to this quadratic function y= (x+4) power of 2 - 8

I am Lyosha [343]

Answer:

Horizontal shift of 4 units to the left.

Vertical translation of 8 units downward.

Step-by-step explanation:

Given the quadratic function, y = (x + 4)² - 8, which represents the horizontal and vertical translations of the parent graph, y = x²:

The vertex form of the quadratic function is y = a(x - h)² + k

Where:

The vertex is (h , k), which is either the <u>minimum</u> (upward facing graph) or <u>maximum</u> (downward-facing graph).

The axis of symmetry occurs at <em>x = h</em>.

<em>a</em> = determines whether the graph opens up or down, and makes the graph wider or narrower.

<em>h</em> = determines how far left or right the parent function is translated.

<em>k</em> = determines how far up or down the parent function is translated.

Going back to your quadratic function,

y = (x + 4)² - 8

The vertex occrs at (-4, -8)
a is assumed to have a value of 1.
Given the value of <em>h</em> = -4, then it means that the graph shifted horizontally by <u>4 units to the left</u>.
Since k = -8, then it implies that the graph translated vertically at <u>8 units downward</u>.

Please mark my answers as the Brainliest, if you find this helpful :)

4 0

2 years ago

WIll mark BRAINLIST plz help

Pani-rosa [81]

F(-1) = 2(-1)^2 + 8(-1)
= 2(1) + (-8)
= -6

3 0

3 years ago

Find the angle between the given vectors to the nearest tenth of a degree. u = <-5, -4>, v = <-4, -3> (1 point)

sesenic [268]

Angle between $u = -5i-4j , v=-4i-3j$ is $x =0$ ° .

<u>Step-by-step explanation:</u>

We have , two vectors u = <-5, -4>, v = <-4, -3> or , $u = -5i-4j , v=-4i-3j$

We need to find angle between these two vectors . Let's find out:

We know that dot product of two vectors is defined as :

$u.v =|u|(|v|)cosx$ , where x is angle between u & v !

⇒ $u.v =|u|(|v|)cosx$

⇒ $cosx =\frac{u.v}{|u|(|v|)}$

Now , $u.v = (-5i-4j)(-4i-3j)$

⇒ $u.v = (-5i-4j)(-4i)-(-5i-4j)(3j)$

⇒ $u.v = 20+12$ { $i(j) = j(i) =0$ }

⇒ $u.v = 32$

Now , Modulus of any vector $r = xi+yj$ is $|r| = \sqrt{x^{2}+y^{2}}$ So ,

$|u| = \sqrt{(-5)^{2}+(-4)^{2}} = \sqrt{25+16} = \sqrt{41} \\\\|v| = \sqrt{(-4)^{2}+(-3)^{2}} = \sqrt{16+9} = \sqrt{25} = 5$

Putting all these values in equation $cosx =\frac{u.v}{|u|(|v|)}$ we get:

⇒ $cosx =\frac{32}{5(\sqrt{41})}$

⇒ $cos^{-1}(cosx) =cos^{-1}(\frac{32}{5(6.4)})$

⇒ $x =cos^{-1}(1)$ { $cos0 = 1$ }

⇒ $x =0$ °

Therefore , Angle between $u = -5i-4j , v=-4i-3j$ is $x =0$ ° .

8 0

3 years ago