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olya-2409 [2.1K]
3 years ago
12

Solve the following problems

Mathematics
1 answer:
Crank3 years ago
7 0
C. [-1 10 0 -9 1 8]
B. [0 -6 3 4 1 -4]
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If (x-2) is a factor of x^3+kx^2 +12x-8 then k=?
AURORKA [14]

Answer:

k = - 6

Step-by-step explanation:

Since (x - 2) is a factor then x = 2 is a root

Substitute x = 2 into the polynomial and equate to zero, that is

2³ + k(2)² + 12(2) - 8 = 0

8 + 4k + 24 - 8 = 0

4k + 24 = 0 ( subtract 24 from both sides )

4k = - 24 ( divide both sides by 4 )

k = - 6

5 0
3 years ago
An astronomy club wants to buy six new eyepieces for their telescope. Four of the lenses cost $53.98 each. Two lenses cost $21 e
Igoryamba
The answer is 257.92 dollars. Comment if you need more help :)
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4 years ago
What is the quotient (x^3-3x^2+3x-2) divided by (x^2-x+1)
Zielflug [23.3K]
If you do the long division you'll see that it is x - 2.
4 0
3 years ago
Use the distributive property to write an equivalent expression: -(n+4)*
stealth61 [152]

Answer: -n-4

Step-by-step explanation:

Distribute the - to n and 4

6 0
4 years ago
Jean transformed a point by using the rule (x,y)(x-6,y+8) the image point is (-4,1) which point is the pre image
Xelga [282]

To find the pre image you need to back track on the image. To get to the image you used (x-6,y+8). Now you need to use the exact opposite to get back to the pre image. For this you would change the signs to look like (x+6,y-8). Now we just apply this to (-4,1).

(-4+6,1-8)

(2,-7) should be the pre image point.

8 0
4 years ago
Read 2 more answers
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