Answer:
x³+3x²+3x+1
Step-by-step explanation:
=(x+1)(x+1)(x+1)
=(x+1)(x²+x+x+1)
=(x+1)(x²+2x+1)
=(x³+2x²+x+x²+2x+1)
=x³+3x²+3x+1
Answer:
Explicit formula: a(n)=3n-6
Recursive formula: a(n)=-3+(n-1)3 <--
Step-by-step explanation:
a(n)=3n-6 where a(1)=3(1)-6=-3 and d=3
<u>Plug values into recursive formula:</u>
a(n)=a1+(n-1)d
a(n)=-3+(n-1)3
52 quadrilaterals would have 52 ÷ 4 = a
a = your answer.
My answer is reasonable because if you have 52 sides from quadrilaterals you would need to divide by 4 to get the amount of quadrilaterals you have. Check your work by multiplying 4 x a = __ (The blank should be 52)
#9 is yes because 12 is double 6. 6+6=12 I don't know #10. Sorry!
What a mysterious expression you have there!
