Answer:
The proved is given below.
Step-by-step explanation:
Given ABCD is a parallelogram and also ∠ABE equals 180°, ∠CBE ≅ ∠CEB
We have to prove that ∠DAE ≅ ∠CEA
As ∠CEA=∠CBE → (1)
and given ABCD is a parallelogram implies AD||CB
∴ ∠DAE=∠CBE → (2) as these are corresponding angles.
From equation (1) and (2), we get
∠DAE=∠CEA
Hence, ∠DAE is congruent to ∠CEA
Hence Proved
Answer:
see below
Step-by-step explanation:
2/3 +y =1/4
Subtract 2/3 from each side
2/3-2/3 +y =1/4-2/3
y = 1/4 -2/3
Get a common denominator
y = 1/4 (3/3) - 2/3 *4/4
= 3/12 - 8/12
=-5/12
or if
2/(y+3) = 1/4
Using cross products
y+3 = 2*4
y+3 = 8
y =8-3
y = 5
1/4q = 3w + 3...multiply both sides by 4
q = 4(3w + 3)
q = 12w + 12 <===
x > -3 and x < 4
in interval notation

>; < - a open circle on the number line and the parenthesis ( or )
≥; ≤ - a filled-in circle on the number line and the parenthesis [ or ]