All categories

3 years ago

X < 4 and x > -3: I need this in interval notation please.

Mathematics

1 answer:

maksim [4K]3 years ago

8 0

x > -3 and x < 4

in interval notation

$x\in(-3,\ 4)$

>; < - a open circle on the number line and the parenthesis ( or )

≥; ≤ - a filled-in circle on the number line and the parenthesis [ or ]

You might be interested in

Write 12.6 as a mixed number with the fraction in simplest form

Naily [24]

Using your knowledge of place value the number is

12 6/10 which then reduces to

12 3/5

6 0

3 years ago

Explain how to estimate 498÷12

PSYCHO15rus [73]

498 is approximately 500

12 is approximately 10

500/10 = 50

So, 498/12 is approximately 50.

8 0

4 years ago

Read 2 more answers

onsider the following problem: A box with an open top is to be constructed from a square piece of cardboard, 3 ft wide, by cutti

Sholpan [36]

Answer:

V (max) = 2 ft³

and x side of the base is x = 0,5 feet

Step-by-step explanation: See annex ( two different cubes)

We have a square piece of cardboard of 3 inches wide

Let x be lenght of side to cut in each corner

Then the base of the (future cube) is 3 - 2x, and the area is

( 3 - 2x )²

And the height is x Then volume of the cube as a function of x is:

V(x) = ( 3 - 2x )² *x or V(x) = ( 9 + 4x² - 12x )*x

V(x) = 4x³ - 12x² + 9x

Taking derivatives on both sides of the equation

V´(x) = 12x² - 24x + 9

V´(x) = 0 12x² - 24x + 9 = 0 simplifying 4x² - 8x + 3 = 0

Second degree equation solving for x

x₁,₂ = [ 24 ± √( 576) - 432 /24

x₁,₂ = [24 ±√144 ]/24

x₁,₂ = ( 24 ± 12) /24 x₁ = 1.5 feet x₂ = 0,5 feet

Of these two values we have to dismiss x₁ because if x = 1.5 we don´t have a cube ( 0 height )

Then we take x = 0,5 feet

And

V (max) = (2)²*0,5 = 4*0,5

V (max) = 2 ft³

5 0

4 years ago

What is the square route of pi

vagabundo [1.1K]

It is simply would be: √π

= √3.14

= 1.7728

In short, Your Answer would be: 1.7728

Hope this helps!

7 0

4 years ago

Read 2 more answers

Segment PE has endpoints P(-4,4) and E(0,-4). Find the coordinates of point Q such that PQ:QE is 1:3. Enter the coordinates belo

Natalka [10]

Answer:

(-3, 2)

Step-by-step explanation:

Given that point Q, partitions segment PE, such that PQ:QE is 1:3, coordinates of point Q is found using the formula below:

$x = \frac{mx_2 + nx_1}{m + n}$

$y = \frac{my_2 + ny_1}{m + n}$

Where,

$P(-4, 4) = (x_1, y_1)$

$E(0, -4) = (x_2, y_2)$

$m = 1, n = 3$

Plug in the necessary values to find x and y coordinates for point Q as follows:

$x = \frac{mx_2 + nx_1}{m + n}$

$x = \frac{1(0) + 3(-4)}{1 + 3}$

$x = \frac{0 - 12}{4}$

$x = \frac{-12}{4}$

$x = -3$

$y = \frac{my_2 + ny_1}{m + n}$

$y = \frac{1(-4) + 3(4)}{1 + 3}$

$y = \frac{-4 + 12}{4}$

$y = \frac{8}{4}$

$y = 2$

The coordinates of the point Q are (-3, 2))

8 0

3 years ago