Question

PLZ HELP Solve the equations for x. 1)ax+bx=13 2)ax+5=cx 3)ax+b=dx−1

Answer 1

Hello there!

ax + bx = 13

We want to start by factorizing out the variable x

x(a + b) = 13

Then divide both sides by a+b

x( a + b)/a + b = 13/a+b

x = $\frac{13}{a+b\\}$

2)

ax + 5 = cx

Should start by adding -cx on both sides

ax + 5 - cx = cx - cx

ax + 5 - cx = 0

ax - cx = 0 - 5

ax - cx = -5

Then again, we need to factor out x because there's two of them

x( a - c) = -5

Then divide both sides by a-c

x(a - c)/ a - c = -5/a - c

x = $\frac{-5}{a-c}$

3)

ax + b = dx - 1

Start by adding -dx on both sides

ax + b - dx = dx - 1 - dx

ax - dx + b = -1

ax - dx = -1 - b

Here we go again, factor out x

x( a - d) = -b - 1

x = $\frac{-b-1}{a-d}$

I hope these answers help. As always, it is my pleasure to help students like you. Let me know if you have additional questions.