Select the inequality that corresponds to the given graph. graph of an inequality with a dashed line through the points negative
3 comma 0 and 0 comma 4 and shading below the line
A. 4x-3y>-12
B. x+4y>4
C. 4x-2y<-8
D. 2x+4y=>-16
A. 4x-3y>-12
B. x+4y>4
C. 4x-2y<-8
D. 2x+4y=>-16
2 answers:
The first thing I did was plot the given two points: (3,0) and (0,4). I connected the two hollow dots and created a line. Then, I shaded the region below the line as mentioned in the problem. The result is show in the picture.
The detail about dashed line is important because it expresses an equality with a symbol < or >. The data points that coincide with that line is not part of the solution but just stand as a boundary, hence, I used dashed line and hollow points. If it were ≥ or ≤, then we use solid lines and dots. With that, we can already eliminate choice D.
Next, we test the inequality. Let's choose a point within the shaded region. Suppose the point is (1,0) denoted by the red dot. If it is part of the solution, then the inequality will be proven true.
<span>A. 4x-3y>-12
4(1) - 3(0) > -12
4 > -12, this is true
B. x+4y>4
1 + 4(0) > 4
1 > 4, this is not true
C. 4x-2y<-8
4(1) -2(0) < -8
4 <-8, this is not true
</span>∴The answer is A.<span>
</span>
The detail about dashed line is important because it expresses an equality with a symbol < or >. The data points that coincide with that line is not part of the solution but just stand as a boundary, hence, I used dashed line and hollow points. If it were ≥ or ≤, then we use solid lines and dots. With that, we can already eliminate choice D.
Next, we test the inequality. Let's choose a point within the shaded region. Suppose the point is (1,0) denoted by the red dot. If it is part of the solution, then the inequality will be proven true.
<span>A. 4x-3y>-12
4(1) - 3(0) > -12
4 > -12, this is true
B. x+4y>4
1 + 4(0) > 4
1 > 4, this is not true
C. 4x-2y<-8
4(1) -2(0) < -8
4 <-8, this is not true
</span>∴The answer is A.<span>
</span>
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