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3 years ago

Whats the equation of a line that passes through (-6,2) andbuas a slope of -(1)/(2)

Mathematics

1 answer:

inysia [295]3 years ago

4 0

I believe your answers are...

Slope Intercept Form:

y= -2x+2

Point Slope Form:

y-2=-2(x-(-6))

Hope this helps.

You might be interested in

We are interested in conducting a study to determine the percentage of voters of a state would vote for the incumbent governor.

Vladimir [108]

Answer:

$n=\frac{0.5(1-0.5)}{(\frac{0.05}{1.96})^2}=384.16$

And rounded up we have that n=385

Step-by-step explanation:

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.05$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

The estimated proportion for this case is $\hat p=0.5$ . And replacing into equation (b) the values from part a we got:

$n=\frac{0.5(1-0.5)}{(\frac{0.05}{1.96})^2}=384.16$

And rounded up we have that n=385

4 0

2 years ago

Please help me

Kruka [31]

y = x^2 -4x

x = -1

y = (-1)^2 - 4×-1=1+4 = 5

x= 0

y = (0)^2 - 4×0 = 0

x = 1

y = 1^2 -4×1 = 1-4 = -3

x = 2

y = 2^2 -4×2 = 4-8 = -4

x=3

y = 3^2 - 4×3 = 9-12 = -3

x = 4

y = 4^2 - 4×4 = 16 - 16 = 0

now 2nd equation

y = 2x^2 + x

x = -2

y = 2 (-2)^2 + (-2)= 8-2 = 6

x = -1

y = 2 (-1)^2+(-1)= 2-1 = 1

x = 0

y = 2(0)^2 +0 = 0

x = 1

y = 2 (1)^2 + 1 = 3

x = 2

y = 2(2)^2+2= 8 + 2 = 10

6 0

2 years ago

Plz help w this math problem

Svetllana [295]

Answer:

• for x = 2a√t, make t the subject:

${ \tt{x = 2a \sqrt{t} }} \\ \\ { \tt{ \sqrt{t} = \frac{x}{2a} }} \\ \\ { \boxed{ \tt{t = \frac{ {x}^{2} }{4 {a}^{2} } }}}$

• then find y:

${ \tt{y = {ar}^{2} - 2at}} \\ \\ { \tt{y = {ar}^{2} - 2a( \frac{ {x}^{2} }{4 {a}^{2} } ) }} \\ \\ { \boxed{ \tt{y = {ar}^{2} - \frac{ {x}^{2} }{2a} }}}$