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Kruka [31]
3 years ago
14

A basketball player participates in a one-and-one free throw situation. The player has a 70% free throw percentage. What is the

average number of points this player will get in 100 one-and-one free throw situations?
Mathematics
2 answers:
Vlad1618 [11]3 years ago
7 0

Answer:

I don't know, I just need points for a question.

Step-by-step explanation:

julia-pushkina [17]3 years ago
3 0

Answer:

The average number of points this player will get in 100 one-and-one free throw situations is 70.

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either the player makes it, or he does not. The probability of the player making a free throw is independent of other free throws. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The expected value of the binomial distribution is:

E(X) = np

70% free throw percentage.

This means that p = 0.7

What is the average number of points this player will get in 100 one-and-one free throw situations?

This is E(X) when n = 100. So

E(X) = np = 100*0.7 = 70

The average number of points this player will get in 100 one-and-one free throw situations is 70.

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