The cube root of 3 is 1.44224957031
Step 1) Multiply 2 by 3
<em>5x+6 = 2x+3x+6</em>
Step 2) Combine like terms
<em>5x+6 = 5x+6</em>
Step 3) Add 5x and 6 to both sides
Answer:
<em>0 = 0</em>
We know that
in the triangle TQS
<span>applying the Pythagorean theorem
QS</span>²=TS²+TQ²---------> TQ²=QS²-TS²--------> TQ²=18²-9x²-----> equation 1
in the triangle TRS
TS²=TR²+RS²--------------> TR²=TS²-RS²-------> TR²=9x²-144----> equation 2
in the triangle QTR
TQ²=TR²+36-----------> equation 3
<span>I substitute 1 and 2 in 3
</span>18²-9x²=9x²-144+36--------> 18x²-432=0------> x²=24-------> x=√24
x=2√6
TS=3*x------> 3*2√6-----> 6√6
TS=6√6 units
the answer is
TS=6√6 units
<span>6 is the square root of 6 units</span>
Answer:
3rd one. The general form of a circle is set equal to the radius squared. So right side is 4 then plug in values until true.
SinC=(8/17)
solve for C = arcsin(8/17)
