Answer:
a) 0.70
b) 0.82
Step-by-step explanation:
a)
Let M be the event that student get merit scholarship and A be the event that student get athletic scholarship.
P(M)=0.3
P(A)=0.6
P(M∩A)=0.08
P(not getting merit scholarships)=P(M')=?
P(not getting merit scholarships)=1-P(M)
P(not getting merit scholarships)=1-0.3
P(not getting merit scholarships)=0.7
The probability that student not get the merit scholarship is 70%.
b)
P(getting at least one of two scholarships)=P(M or A)=P(M∪A)
P(getting at least one of two scholarships)=P(M)+P(A)-P(M∩A)
P(getting at least one of two scholarships)=0.3+0.6-0.08
P(getting at least one of two scholarships)=0.9-0.08
P(getting at least one of two scholarships)=0.82
The probability that student gets at least one of two scholarships is 82%.
Horizontal shift 1 unit left and vertical shift 11 units up
The answer is 300 or 3*10^2
Answer:
28..
Step-by-step explanation:
divide 35 by 1 1/4...
Use Pythagorean theorem (a squared is equal to c squared minus b squared)
Where a is the unknown leg, c is the hypotenuse and b is the known leg
a^2 = 13^2-5^2 which is 144
Then square root one hundred and fourty four to get rid of the power on a
Square root of one hundred and fourty four is twelve
