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2 years ago

Simplify 45÷2×8-12+42 Please show working

Mathematics

1 answer:

Allushta [10]2 years ago

6 0

Answer:

210

Step-by-step explanation:

Lets use BEDMAS (Brackets, Exponents, Division, Multiplication, Addition, Subtraction)

45 ÷ 2 = 22.5

22.5 × 8 = 180

180 - 12 = 168

168 + 42 = 210

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Have a great summer :)

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Please can someone help

Sergeu [11.5K]

Answer = £44,918

220x8.8 = 1936
2.3x2.1 = 4.83
1936 + 4.83 = 1940.83
1940.83/1.6 = 1213.01
1214x37 = 44918

6 0

2 years ago

Can someone help me please

N76 [4]

26/100 or simplified to 13/50

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2 years ago

The volume of a prism with side lengths measured in millimeters is 20. How could this measurement be written? Check all that app

Katyanochek1 [597]

The unit measurement of the a volume in mm is mm³(millimetres cube.)

<h3>How to find volume ?</h3>

Volume is is defined as the space occupied within the boundaries. The objects are usually solid objects.

The volume of a 3 dimensional figure is the product of the base area and the height.

Therefore, the units of volume is measured in cubic units.

The volume of a prism with side lengths measured in millimetres is 20.

Therefore, the measurement can be represented as follows:

20 mm³

learn more on volume here: brainly.com/question/16310824

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1 year ago

The perimeter of a rectangle is 66 feet. The width is 15 ft less than 1/2 the length. Find the dimensions of the figure

lianna [129]

The length is 32 and the width is 1. 32÷2 is 16. 16-15 is 1. 32+32+1+1 is 66

8 0

2 years ago

A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters

In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

$\Rightarrow y=\sqrt{x^2+100}$

Differentiating with respect to t

$\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}$

$\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}$

Since the car driving towards the intersection at 13 m/s.

so, $\frac{dx}{dt}=-13$

$\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)$

Now

$\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)$

$=\frac{24\times (-13)}{\sqrt{676}}$

$=\frac{24\times (-13)}{26}$

= -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0

2 years ago