Question
Help, please!!
How much is 2/5 of 20 ?
Answer:
8
Step-by-step explanation:
20 * 2/5 =
8
----------------------
20 : 5 * 2 = 8
Complete Question
Educational Television In a random sample of 200 people, 159 said that they watched educational television. Find the 90% confidence interval of the true proportion of people who watched educational television. Round the answers to at least three decimal places.
Answer:
The 90% confidence interval is
Step-by-step explanation:
From the question we are told that
The sample size is n = 200
The number of people that watched the educational television is 
Generally the sample proportion is mathematically represented as

=> 
From the question we are told the confidence level is 90% , hence the level of significance is
=>
Generally from the normal distribution table the critical value of
is
Generally the margin of error is mathematically represented as
=>
=>
Generally 95% confidence interval is mathematically represented as
=>
=>
<h2>
Answer with explanation:</h2>
According to the Binomial probability distribution ,
Let x be the binomial variable .
Then the probability of getting success in x trials , is given by :
, where n is the total number of trials or the sample size and p is the probability of getting success in each trial.
As per given , we have
n = 15
Let x be the number of defective components.
Probability of getting defective components = P = 0.03
The whole batch can be accepted if there are at most two defective components. .
The probability that the whole lot is accepted :

∴The probability that the whole lot is accepted = 0.99063
For sample size n= 2500
Expected value : 
The expected value = 75
Standard deviation : 
The standard deviation = 8.53
Yes I worked it in my brain hahahahahah
Answer:
Step-by-step explanation:
The highest power of x here is 3, so this is a third degree polynomial. Since the coefficient of the highest power term is +, we know that the graph approximates that of the parent function y = x^3, and that this graph begins in Quadrant III, enters Quadrant I and continues to move upward in Quadrant I.