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Lesechka [4]
3 years ago
10

Lia must work at least 5 hours per week in her family’s restaurant for $8 per hour. She also does yard work for $12 per hour. Li

a’s parents allow her to work a maximum of 15 hours per week overall. Lia’s goal is to earn at least $120 per week.
Write a system of inequalities to represent this situation. Let r be the number of hours worked at the restaurant, and let y be the number of hours of yard work.
Graph the inequalities.
What is the maximum number of hours Lia can work at the restaurant and still meet her earnings goal? Explain.
What is the maximum amount of money Lia can earn in 1 week? Explain.
Mathematics
1 answer:
Sedaia [141]3 years ago
4 0
Hello,

As the question states, let r be the number of hours worked at the restaurant, and y be the number of hours of yard work. We know that she can only work a maximum of 15 hours per work total, and that at she must work at least 5 hours in the restaurant. Therefore:r + y ≤ 15r ≥ 5We also know that she wants to earn at least 120 dollars, earning $8/hr in the restaurant and $12/hr in the yard:8r + 12y ≥ 120
What is the maximum of hours Lia can work in the restaurant and still make at leas 120 hours? Lia's parents won't let her work more than 15 hours, so we know that the answer won't be higher than 15.If she worked all 15 hours in the restaurant, she would make 8*15 = 120.The maximum number of hours she can work in the restaurant is therefore 15 hours
What is the maximum amount of money Lia can earn in a week? Lia has to work a minimum of 5 hours in the restaurant. She makes more money doing yard work, so she should devote the rest of her available work hours to yard work. That means that, given her 15 hour work limit, she will maximize her income by working 5 hours in the restaurant and 10 hours in the yard. 5*8 + 10*12 = 40 + 120 = 160The most she can make is 160 dollars, working 5 hours in the restaurant and 10 hours in the yard

Hope this helps

~Girlygir101~
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Step-by-step explanation:

The club must have 6 juniors and 8 seniors

We have a total of 13 juniors and 16 seniors.

Now, we know that the possible combinations of N objects into a group of K is equal to:

C = \frac{N!}{(N-K)!*K!}

For the juniors we have N = 13 and K = 6

Cj = \frac{13!}{7!*6!} = \frac{13*12*11*10*9*8}{6*5*4*3*2*1} = 1716

For the seniors we have N = 16 and K = 8

Cs = \frac{16!}{8!8!}  = \frac{16*15*14*13*12*11*10*9}{8*7*6*5*4*3*2*1} = 12870

Now, as the group consist on both combinations togheter, the number of different clubs that can be formed are:

C = Cj*Cs = 1,716*12,870 = 22,084,920

5 0
3 years ago
58​% of U.S. adults have very little confidence in newspapers. You randomly select 10 U.S. adults. Find the probability that the
geniusboy [140]

Answer:

.216165788

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Step-by-step explanation:

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A.

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B.

I honestly think the fastest way to solve this is adding the probabiblity of exactly 6,7,8,9,10

which means we write

10C6*.58⁶*(1-.58)⁴+10C7*.58⁷*(1-.58)³+10C8*.58⁸*(1-.58)²+10C9*.58⁹*(1-.58)+10C10*.58¹⁰= .582225057

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Answer:

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so A = 0.83 cube root

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Alex17521 [72]

Answer:

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Step-by-step explanation:

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