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jolli1 [7]
3 years ago
11

Where does the pythagorean identity sin^2 + cos^2=1 come from? How does it relate to right triangles?

Mathematics
1 answer:
Arada [10]3 years ago
8 0
Consider a<span> right triangle with </span><span>hypotenuse of 1.
sin x means to divide the side in front of the angle by </span>hypotenuse<span>
cos x means to divide the side beside  the angle by hypotenuse
we know that a^2+b^2=c^2 now divide two sides by c^2
\frac{ a^{2} }{ c^{2} }+  \frac{ b^{2} }{ c^{2} }=1
c is 1 also a/c means sinx and b/c is cos x so
sin^2(x)+cos^2(x)=1

</span>



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The distribution of prices for home sales in a certain New Jersey county is skewed to the right with a mean of $290,000 and a st
I am Lyosha [343]

Answer:

The probability that the mean of the sample is greater than $325,000

P( X > 3,25,000) = P( Z >2.413) = 0.008

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given the mean of the Population( )= $290,000

Standard deviation of the Population = $145,000

Given the size of the sample 'n' = 100

Given 'X⁻'  be a random variable in Normal distribution

Let   X⁻ = 325,000

Z = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }  = \frac{325000-290000}{\frac{145000}{\sqrt{100} } }  = 2.413

<u><em>Step(ii):</em></u>-

The probability that the mean of the sample is greater than $325,000

P( X > 3,25,000) = P( Z >2.413)

                           = 0.5 - A(2.413)

                           = 0.5 - 0.4920

                           = 0.008

<u><em>Final answer:-</em></u>

The probability that the mean of the sample is greater than $325,000

P( X > 3,25,000) = P( Z >2.413) = 0.008

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Write the standard form of the equation of a circle with radius 3 and center (11, 3)
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Answer:

<u>x² - 22x + y² - 6y + 121 = 0</u>

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<u>General Form of Equation</u>

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<u>Solving</u>

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  • <u>x² - 22x + y² - 6y + 121 = 0</u>
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3 years ago
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Answer:

$0.80

Step-by-step explanation:

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Need help on 15 and 16 PLEASEE!!!
melisa1 [442]

Answer:

Part 15) The next three terms are 5/8,3/4 and 7/8

Part 16) The 37th term is -35.5

Step-by-step explanation:

we know that

In an <u>Arithmetic Sequence</u> the difference between one term and the next is a constant and this constant is called the common difference (d)

Part 15) Find the next three terms of the arithmetic sequence

\frac{1}{8},\frac{1}{4},\frac{3}{8},\frac{1}{2},...

so

a1=1/8\\ a2=1/4\\ a3=3/8\\ a4=1/2\\ a2-a1=1/4-1/8=1/8\\ a3-a2=3/8-1/4=1/8\\ a4=a3=1/2-3/8=1/8

The common difference is equal to

d=1/8

<u><em>Find the next three terms of the arithmetic sequence</em></u>

<u><em>Find a5</em></u>

a5=a4+d ----->a5=1/2+1/8=5/8

<u><em>Find a6</em></u>

a6=a5+d ----->a6=5/8+1/8=3/4

<u><em>Find a7</em></u>

a7=a6+d ----->a7=3/4+1/8=7/8

therefore

The next three terms are

5/8,3/4 and 7/8

Part 16) what is the 37th term of the arithmetic sequence

4.1,3,1.9,0.8,...?

so

a1=4.1\\ a2=3\\ a3=1.9\\ a4=0.8

a2-a1=3-4.1=-1.1\\ a3-a2=1.9-3=-1.1\\ a4=a3=0.8-1.9=-1.1

The common difference is equal to

d=-1.1

We can write an Arithmetic Sequence as a rule

an=a1+d(n-1)

substitute the values

an=4.1-1.1(n-1)

For n=37

substitute

a37=4.1-1.1(37-1)

a37=4.1-1.1(36)

a37=-35.5

4 0
3 years ago
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