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Bas_tet [7]
4 years ago
11

The greater of two consecutive even integers is eleven more than half the lesser. Determine the integers.

Mathematics
1 answer:
exis [7]4 years ago
5 0
<span>The lesser of two consecutive even integers is 10 more than one-half the greater. Find the integers.
1st: 2x
2nd: 2x+2
-----
EQUATION:
2x =(1/2)(2x+2)+10
2x = x + 11
x = 11
-------------
1st: 2x = 22
2nd: 2x + 2 = 24
=================================== 

2) The greater of two consecutive even integers is 6 less than the times the lesser


</span><span>3) Find four consecutive integers such that twice the sum of the two greater integers exceeds three times the first by 91. 
1st: x
2nd: x+1
3rd: x+2
4th: x+3
---------------
EQUATION:
2(x+2 + x+3) = 3x + 91
4x + 12 = 3x + 91
x = 79
x+1 = 80
etc.
====================== 
4) Find a set of four consecutive positive integers such that the greatest integer in the set is twice the least integer in the
I'll leave this to you.</span>
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Answer:

\mathrm{Slope=== > 0}

Step-by-step explanation:

Hi student, let me help you out!

<u>.............................................................................................................</u>

<u></u>

First, let's recall the slope formula: \boxed{\mathrm{\cfrac{y2-y1}{x2-x1}}}}, where y2 and y1 are y-coordinates; x2 and x1 are x-coordinates.

Plugin the values: \mathrm{\cfrac{0-0}{-17-(-9)}}.

Upon simplifying, we obtain \mathrm{\cfrac{0}{-17+9}}.

Upon simplifying this further, we obtain \mathrm{\cfrac{0}{-9}}.

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Hope this helped you out! Ask in comments if even the slightest queries arise.

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