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nignag [31]
4 years ago
12

Vertex of f(x)=0.25|x-3|

Mathematics
1 answer:
Sonbull [250]4 years ago
4 0

Answer:

(3,0)

Step-by-step explanation:

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Please help with the answer below
kenny6666 [7]

Answer:

f(x) =  \frac{x + 7}{6 - x}  \\  \frac{3}{2}  =  \frac{x + 7}{6 - x}  \\ 3(6 - x) = 2(x + 7) \\ 18 - 3x = 2x + 14 \\  - 3x - 2x = 14 - 18 \\  - 5x =  - 4 \\  \frac{ - 5x}{ - 5}  =   \frac{ - 4}{ - 5}  \\ x =  \frac{4}{5}

3 0
3 years ago
3. Create three quadratic equations that has one real solution.​
Verizon [17]

Three quadratic equations that have one real solution are show below:

5x^2+3x^3+3^4 = 55

5x^2+3x^3+3^7 = 55

5x^2+3x^3+3^8 = 55

7 0
3 years ago
el producto de tres números es 1000 y su suma es 39. Si se sabe que el primero es al segundo como el segundo es al tercero, hall
pentagon [3]

Answer: The difference between the larger and smaller number is 21.

Step-by-step explanation:

This can be translated to:

"the multiplication between 3 numbers is 1000 and the addition is 39.

If the first number is at the second like the second at the third, find the difference between the smaller and the larger number"

If A is the first number, B the second and C the third we have that:

A*B*C = 1000

A + C + B = 39

A/B = B/C

From the third equation we have that:

A*C = B*B

we can replace it in the first equation and get:

B*(A*C) = 1000

B*B*B = B^3 = 1000

B = \sqrt[3]{1000} = 10

So now we have the value of B.

Now we have the two equations:

A + 10 + C = 39

A*C = B*B = 10*10 = 100

We can isolate A in the first equation and get:

A = 39 - 10 - C = 29 - C

now we can replace it in the second equation:

(29 - C)*C = 100

29C - C^2 - 100 = 0

We need to find the roots of that equation, we can use the Bhaskara's function:

C = \frac{-29 +- \sqrt{29^2 - 4*(-1)*(-100)} }{2*(-1)} = \frac{-29 +- 21}{-2}

Where we have two possible values for C

C = (-29 - 21)/(-2) = 25

C = (-29 + 21)/(-2) = 4

Let's chose C = 4, because C is the smaller value. (A will take the other value)

Then we have:

A + B + C = 39

A + 10 + 4 = 39

A = 39 - 14 = 25

Then the difference between the larger and smaller number is:

A - C = 25 - 4 = 21

4 0
4 years ago
Rhombus A B C D is shown. Lines are drawn from point A to point C and from point D to point B and intersect at point E. All side
gavmur [86]
Area of rhombus = 1/2 * diagonal * diagonal

72 = 1/2 * AC * BD

Diagonals bisect each other in a rhombus so if EC is 8 then AC is 16

72 = 1/2 * 16 * x - 1
72 = 8(x-1)
9 = x-1
X = 10

Check
72 = 1/2 * 16 * 10-1
72 = 1/2 * 16 * 9
72 = 8 * 9
72=72
4 0
2 years ago
Read 2 more answers
If AD=6 and AB=24, find AC
ruslelena [56]
When a perpendicular is dropped from the right-angle (C) to the opposite side AB, the metric relations apply:
BD*BA=a^2 ..........................(1)
AD*AB=b^2...........................(2)
BD*DA=DC^2........................(3)

Given AD=6, AB=24, using metric relation (2) above, we have
b^2=6*24=144
=>
b=sqrt(144)=12

By the way, we conclude that this is a 30-60-90 triangle because b/AB=(1/2)=sin(B) => B=30 degrees.

Answer: b=12
6 0
3 years ago
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