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Evgesh-ka [11]
3 years ago
11

3. Create three quadratic equations that has one real solution.​

Mathematics
1 answer:
Verizon [17]3 years ago
7 0

Three quadratic equations that have one real solution are show below:

5x^2+3x^3+3^4 = 55

5x^2+3x^3+3^7 = 55

5x^2+3x^3+3^8 = 55

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What's the question?
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3 years ago
HELP!!! I NEED A ANSWER ASAP
hichkok12 [17]

Answer:

Hundred Digit = 7

Ten Digit = 7

Unit Digit = 3

Number = 773

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Multiply. (2x2 + 4x - 3)(x2 - 2x + 5)
BigorU [14]
For a moment, let y=x^2-2x+5. Then by the distributive property,

(2x^2+4x-3)p=2x^2p+4xp-3p


Again by the distributive property,

2x^2p=2x^2(x^2-2x+5)=2x^4-4x^3+10x^2

4xp=4x(x^2-2x+5)=4x^3-8x^2+20x

-3p=-3(x^2-2x+5)=-3x^2+6x-15

Taking everything together, we get

(2x^2+4x-3)(x^2-2x+5)=(2x^4-4x^3+10x^2)+(4x^3-8x^2+20x)+(-3x^2+6x-15)
(2x^2+4x-3)(x^2-2x+5)=2x^4-x^2+26x-15
7 0
3 years ago
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Find the volume of the cone​
irina1246 [14]

Answer:

The volume of the cone is 12936 cubic mm.

Step-by-step explanation:

Given

Circumference of base = 132 mm

Height of the cone = 28 mm

Solution

Formula  of circumference = 2\pi r = 132 mm

\therefore\ r= \frac{132}{2 \pi } = 21 mm

Now volume of cone = \frac{1}{3} \times\pi \times r^{2} \times h

on substituting the value of r and h  we get ;

\frac{1}{3}\times\frac{22}{7} \times21\times21\times28= 12936\ mm

thus volume of cone is 12936  cubic mm.

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3 years ago
ANSWER ALL FOR BRAINLIEST and lots of points with explanation !!!!ASAP!!
castortr0y [4]

Answer:

here you go

Step-by-step explanation:

20) 3125.76

do 4%*8= 0.32 then 0.32*9768=3125.76

21) Evan- 10%, Jordan-26%, Curt 64%

22) 22 votes (the answer would be 22.62 but you have to round down)

7 0
3 years ago
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