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pentagon [3]
2 years ago
7

which solution below would be considered the most acidic?a. 2.9 x 10-4 m hclb. 4.5 x 10-5 m hno3c. 1.0 x 10-7 m nacld. 1.5 x 10-

2 m kohe. none of the above
Chemistry
1 answer:
kkurt [141]2 years ago
7 0

Answer:

a. 2,9x10⁻⁴ M HCl

Explanation:

A solution is considered acidic when its concentration of H⁺ is higher than 1x10⁻⁷. The higher concentration of H⁺ will be the most acidic solution.

a. 2,9x10⁻⁴ M HCl. In water, this solution dissolves as H⁺ and Cl⁻. That means concentration of H⁺ is 2,9x10⁻⁴ M.

b. 4,5x10⁻⁵M HNO₃. In the same way, concentration of H⁺ is 4,5x10⁻⁵M.

c. 1,0x10⁻⁷M NaCl. As this solution doesn't produce H⁺, the solution is not acidic

d. 1,5x10⁻²M KOH. This solution produce OH⁻. That means the solution is basic nor acidic.

Thus, the solution considered the most acidic is a. 2,9x10⁻⁴ M HCl, because has the higher concentration of H⁺.

I hope it helps!

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What NaCl NaCl concentration results when 249 mL 249 mL of a 0.850 M 0.850 M NaCl NaCl solution is mixed with 667 mL 667 mL of a
tamaranim1 [39]

Answer:

The answer to your question is 0.54M

Explanation:

Data

Final concentration = ?

Concentration 1 = 0.850 M

Volume 1 = 249 ml = 0.249 l

Concentration 2 = 0.420 M

Volume 2 = 0.667 M

Process

1.- Calculate the number of moles in both solutions

Number of moles 1 = Molarity 1 x Volume 1

                               = 0.850 x 0.249

                               = 0.212

Number of moles 2 = Molarity 2 x Volume 2

                                = 0.420 x 0.667

                                = 0.280

Total number of moles =  0.212 + 0.280

                                      = 0.492

2.-Calculate the final volume

Final volume = Volume 1 + Volume 2

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