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oksano4ka [1.4K]
3 years ago
8

14) The central iodine atom in the ICl4- ion has __________ nonbonded electron pairs and __________ bonded electron pairs in its

valence shell.
Chemistry
1 answer:
masha68 [24]3 years ago
7 0

Answer:

Two non bonded electron pairs and four bonded electron pairs

Explanation:

An image of the compound as obtained from chemlibretext is attached to this answer.

The ion ICl4- ion, is an AX4E2 ion. This implies that there are four bond pairs and two lone pairs of electrons. As expected, the shape of the ion is square planar since the lone pairs are found above and below the plane of the square. This is clear from the image attached.

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7. A square chunk of plastic has a length of 5 cm, width of 5 cm and height of 5 cm. It has a mass of 200 g. What is its density
BaLLatris [955]

Answer:

d=1.6\ g/cm^3

Explanation:

Given that,

The dimension of a square chunk of plastic is 5 cm × 5 cm × 5 cm

Mass, m = 200 g

We need to find its density

Density = mass/volume

It will form a cube. It volume = side³

So,

d=\dfrac{200\ g}{5^3\ cm^3}\\\\d=1.6\ g/cm^3

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5 0
4 years ago
Given the following data, determine the order of reaction with respect to H2.
alex41 [277]

Answer:

First-order with respect to hydrogen.

Explanation:

Hello!

In this case, considering that the rate law of this reaction can be expressed via:

r=k*p_{H_2}^m*p_{ICl}^n

If we want to know m, the order of reaction with respect to hydrogen, we need to relate the experiments 1 and 3 in order to get rid of the pressure of ICl:

\frac{r_1}{r_3} =\frac{k*p_{H_2,1}^m*p_{ICl,1}^n}{k*p_{H_2,3}^m*p_{ICl,3}^n}

Thus, we plug in the given rates, and pressures to get:

\frac{1.34}{0.266} =\frac{k*250^m*325^n}{k*50^m*325^n}

So we can cancel wout k and 325^n:

\frac{1.34}{0.266} =\frac{250^m}{50^m}

Next we solve for m, the order of reaction with respect to hydrogen:

5.04 =5^m\\\\log(5.04)=m*log(5)\\\\m=\frac{log(5.04)}{log(5)} \\\\m=1.0

It means it is first-order with respect to hydrogen.

Regards!

7 0
3 years ago
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Answer:

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Explanation:

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The question requests us to identify the process that has a negative change of entropy.

carbon dioxide(g) → carbon dioxide(s)

There is  a change in state from gas to solid. Solid particles are more ordered than gas particles so this is a negative change in entropy.

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propanol (g, at 555 K) → propanol (g, at 400 K)

Temperature is directly proportional to entropy, this means higher temperature leads t higher entropy.

This reaction highlights a drop in temperature which means a negative change in entropy.

methyl alcohol condenses

Condensation is the change in state from gas to liquid. Liquid particles are more ordered than gas particles so this is a negative change in entropy.

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