The molarity of a solution prepared by dissolving 3.11 grams of NaOH in
enough water to make 300 milliliters of solution is 0. 256 mol/ L
Explanation:
<h3>
What is Molarity?</h3>
Molarity (M) is the amount of a substance in a given volume of solution. It is otherwise known as the number of moles of solute in a certain amount of solution.
The unit of molarity is mol/L
<h3>Formula for calculating molarity :</h3>
Molarity = number of moles of solute divided by the volume of the solution\
<h3>Parameters </h3>
Molarity = ?
Number of moles is calculated using :
Mass of the solute = 3.11 grams of NaOH
Molar mass of the solute = Na + O + H
Let's input the atomic numbers of the elements: Na (23) , O (16) , H (1)
Molar mass of NaOH = 23 + 16 + 1 = 40 g/ mol
Number of moles = 3.11 ÷ 40 = 0.077 mol
Volume of the solution is measured in Liters
Let's convert 300 milliters to liters = 300 divided by 1000 = 0.3 Liters
Molarity = 0.077 ÷ 0.3 = 0. 256 mol/ L
Therefore, the Molarity of the solution is 0. 256 mol/ L
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