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kkurt [141]
3 years ago
11

Niobium-91 has a half-life of 680 years. After 2,040 years, how much niobium-91 will remain from a 300.0-g sample? 3 g 18.75 g 3

7.5 g 100.0 g
Chemistry
2 answers:
Vadim26 [7]3 years ago
7 0
Amount of Niobium-91 initially
= 300/91 =3.2967mol
2040 years = 3 ×680 = 3 half-lives
therefore, amount left = 0.4121mol
mass of Niobium-91 remaining = 0.4121 ×91 =37.5g
Maslowich3 years ago
7 0
The correct answer is letter c 


hope i helped
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A sealed flask containing 1.0 mole of H2(g) and a sealed flask containing 2.0 moles of He(g) are at the same temperature. The tw
irinina [24]

Answer:

Pressure or Average Kinetic Energy

Explanation:

When dealing with sealed containers filled with gas, there are many variables to consider. Namely: pressure, temperature, volume, number of molecules present.

However, this question can be solved easily, without worrying too much about the other variables. Usually the case is that if there is a difference in pressure, there will be a difference in temperature, so the answer could be that both pressures must be equal.

Another way we could look at it is that the Average Kinetic Energies between the two containers have to be equal, and this will then lead to the temperatures being equal without worrying about other variables.

8 0
3 years ago
What is convection cell​
kkurt [141]

Answer:

Explanation:

a self-contained convective zone in a fluid in which upward motion of warmer fluid in the center is balanced by downward motion of cooler fluid at the periphery.

3 0
3 years ago
Which of the following is not equal to 485 L?
ELEN [110]

Answer:

4.85 * 10^4\ mL

Explanation:

Given

485 L

Required

Determine the measurement not equal to 485L

0.485\ kL

<em>From standard unit of conversion;</em>

1 KL = 1000 L

<em>Multiply both sides by 485</em>

485 * 1 KL = 485 * 1000 L

485KL = 485000L

<em>Divide both sides by 1000</em>

\frac{485KL}{1000} = \frac{485000L}{1000}

0.485KL = 485L  ---- This is equivalent

---------------------------------------------------------------------------------------------

4.85 * 10^4\ mL

<em>From standard unit of conversion;</em>

1000 mL = 1 L

<em>Multiply both sides by 485</em>

485 * 1000 mL = 1 L * 485

485000\ mL = 485\ L

Convert to standard form

4.85 * 10^5\ mL = 485\ L

Hence; 4.85 * 10^4\ mL is not equivalent to 485L

---------------------------------------------------------------------------------------------

48500 \ cL

<em>From standard unit of conversion;</em>

100 cL = 1 L

<em>Multiply both sides by 485</em>

485 * 100 cL = 1 L * 485

48500\ cL = 485\ L

Convert to standard form

4.85 * 10^4\ cL = 485\ L ---- This is equivalent

---------------------------------------------------------------------------------------------

4.85 * 10^8 \ μL

<em>From standard unit of conversion;</em>

1000000 μL = 1 L

<em>Multiply both sides by 485</em>

485 * 1000000uL  = 1 L * 485

485000000uL = 485\ L

Convert to standard form

4.85 * 10^8\ uL = 485\ L ---- This is equivalent

From the list of given options;

4.85 * 10^4\ mL is not equivalent to 485L

4 0
3 years ago
5. A sample of gas occupies 1.55 L at 27 degrees Celsius and 1.00 atm pressure. What will the volume be if the pressure is incre
Sergio039 [100]

Answer:

The volume will be 0.031 L

Explanation:

Since temperature is constant, Boyle's law is applied in this case.

Boyle's law States that at constant temperature, the volume of a given mass of a gas is inversely proportional to it's pressure.

From this statement it was deduced that P1V1 = P2V2

From the question, P1 = 1atm, V1 = 1.55L, P2 = 50 atm and V2 is to be calculated.

V2 = P1V1/P2

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5 0
3 years ago
HELPP!<br> how many grams are in 1.50 x 10(24) atoms of copper?
svlad2 [7]

Answer:

2266g

Explanation:

mass = no.of molecules /6.o23*1o(23) * molar mass

molar mass of co2= 44g /mol

1.5 .10^25/6.023 .10^23 =51.5 moles of co2

51.5 .44g/mol =2266 g

4 0
3 years ago
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