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2 years ago

wrote an equation for the line. passing through (-5,7) and parallel to the line whise equation is 5x-3y-4=0

Mathematics

1 answer:

xeze [42]2 years ago

3 0

Step-by-step explanation:

5x-3y-4=0---------(1)

Slope = - coefficient of X/ coefficient of y

= -5/(-3)

= 5/3

(x1,y1)= (-5,7)

Equation of the line,

Y-Y1= slope(X-X1)

Y-7= (5/3)×(X-(-5))

Y-7= (5x+25)/3

3y-7=5x+25

5x-3y+32=0 is the required eqn

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Step-by-step explanation:

lets split this into two shapes:

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1 year ago

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Solve the following equation by completing the square. Enter your answers from smallest to largest. Round your answer you answer

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2 years ago

Y = 4x – 18 y = -5x +9

adelina 88 [10]

Answer:

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General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

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Parenthesis
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Left to Right

Equality Properties

Multiplication Property of Equality
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Algebra I

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Step-by-step explanation:

Step 1: Define Systems

y = 4x - 18

y = -5x + 9

Step 2: Solve for x

Substitution

Substitute in y [2nd Equation]: 4x - 18 = -5x + 9
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ivolga24 [154]

Answer:

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(a)

Compute the probability that a person passes the security system using the total probability rule as follows:

The total probability rule states that: $P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})$

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Thus, the probability that a person passes the security system is 0.9412.

(b)

Compute the probability that a person who passes through the system is without any security problems as follows:

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Answer:

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Step-by-step explanation:

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refer to the image below to see what that means

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wrote an equation for the line. passing through (-5,7) and parallel to the line whise equation is 5x-3y-4=0​

wrote an equation for the line. passing through (-5,7) and parallel to the line whise equation is 5x-3y-4=0