The required point-slope form of the equation of the line is y - 5 = -4(x + 1).
Given that, To determine an equation in point-slope form for the line that passes through the point with the given slope. point: (-1, 5) and m=-4.
What is the slope of the line?
The slope of the line is a tangent angle made by line with horizontal. i.e. m =tanx where x in degrees.
Here,
The point-slope of the equation of the line is given by,
y - y₁ = m(x - x₁)
Put the values in the above equation of the line
y - 5 = -4 (x - (-1))
y - 5 = -4 (x + 1)
Thus, the required point-slope form of the equation of the line is y - 5 = -4(x + 1).
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Lol, bro, 15.68 is your solution
Answer:
-2.35
Step-by-step explanation:
Divide -4.7/2 = -2.35
Answer:
D. y = -1/5x +32/5
Step-by-step explanation:
The equation of the line passing through point (h, k) with slope m can be written ...
y = m(x -h) +k
Filling in your given values, the equation is ...
y = -1/5(x -(-3)) +7
y = -1/5x -3/5 +7 . . . . eliminate parentheses
y = -1/5x +32/5 . . . . . combine constants
