What is (3i-2/3)-(6i-5) in standard form
1 answer:
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Answer:
4th option
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = x - 6 ← is in slope- intercept form
with slope m =
Given a line with slope m then the slope of a line perpendicular to it is
= -
= -
= -
The equation of a line in point- slope form is
y - b = m(x - a)
where m is the slope and (a, b) a point on the line
Here m = - and (a, b ) = (- 2, 5 ) , then
y - 5 = - (x - (- 2) ) , that is
y - 5 = - (x + 2)
<h2>Explanation:</h2>
Let's use a trial and improvement method to find this solution.
Step 1. Let's choose x = 8.5
Substituting into the equation:
Step 2. Let's choose x = 8.4
Substituting into the equation:
Step 3. Let's choose x = 8.3
Substituting into the equation:
Since the sign of the equation changes from positive to negative when evaluating from 8.4 to 8.3, then x = 8.3 seems to be a reasonable value. Finally, the solution to 1 decimal place is: