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Anit [1.1K]
3 years ago
13

What is (3i-2/3)-(6i-5) in standard form

Mathematics
1 answer:
k0ka [10]3 years ago
5 0

Answer:

13/3 -3i

Step-by-step explanation:

(3i-2/3)-(6i-5)

Distribute the minus sign

(3i-2/3)-6i+5

Combine like term

-2/3 +5  +3i - 6i

-2/3 +15/3   -3i

13/3 -3i

This is standard form

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nalin [4]

Hi!

<h3>Put in the values. </h3>

[z+8(5-2)]^2/4

<h3>Now use PEMDAS to solve. </h3>
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[z+8*3]^2/4

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[z+24]^2/4

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  • Division

<u>z+144</u>

<h2>When you evaluate [a+8 (b-2)]^2÷4, you get z + 144</h2>

Hope this helps! :)

-Peredhel

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Step-by-step explanation:

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3 years ago
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How do i use properties of exponents
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You can use the properties of exponents in three ways: Products of Power and Power to Power


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