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Anit [1.1K]
3 years ago
13

What is (3i-2/3)-(6i-5) in standard form

Mathematics
1 answer:
k0ka [10]3 years ago
5 0

Answer:

13/3 -3i

Step-by-step explanation:

(3i-2/3)-(6i-5)

Distribute the minus sign

(3i-2/3)-6i+5

Combine like term

-2/3 +5  +3i - 6i

-2/3 +15/3   -3i

13/3 -3i

This is standard form

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