Answer:
<u>Part 1:</u>
For Platinum Gym:
90 + 30x
For Super Fit Gym:
200 + 20x
<u>Part 2:</u> $270
<u>Part 3:</u> $320
<u>Part 4:</u> 11 months
<u>Part 5:</u> See explanation below
Step-by-step explanation:
<u>Part 1:</u>
Let "x" be the number of months:
For Platinum Gym:
90 + 30x
For Super Fit Gym:
200 + 20x
<u>Part 2:</u>
We put x = 6 in platinum gym's equation and get our answer.
90 + 30x
90 + 30(6)
90 + 180
=$270
<u>Part 3:</u>
We put x = 6 into super fit's equation and get our answer.
200 + 20x
200 + 20(6)
200 + 120
=$320
<u>Part 4:</u>
To find the number of months for both gyms to cost same, we need to equate both equations and solve for x:
90 + 30x = 200 + 20x
10x = 110
x = 11
So 11 months
<u>Part 5:</u>
We know for 11 months, they will cost same. Let's check for 10 months and 12 months.
In 10 months:
Platinum = 90 + 30(10) = 390
Super Fit = 200 + 20(10) = 400
In 12 months:
Platinum = 90 + 30(12) = 450
Super Fit = 200 + 20(12) = 440
Thus, we can see that Platinum Gym is a better deal if you want to get membership for months less than 11 and Super Fit is a better deal if you want to get membership for months greater than 11.
Answer:
(15m^2 + 5)
Step-by-step explanation:
(m2 - 3m + 19 ) + (2m2 + m) + (4m2 - 7) + (2m2 + m) + (4m2 - 7) + (2m2 + m)
15m2 + 0m + 5
=> <u>15m^2 + 5</u>
Amount Financed: $2,650
Finance Charge: $484.69
Number of Payments: 36
(Finance Charge)/(Amount Financed)*100$=($484.69)/($2,650)*100$
(Finance Charge)/(Amount Financed)*100$=(0.1829)*100$
(Finance Charge)/(Amount Financed)*100$=$18.29
In the row of number of Payments 36, we look for:
(Finance Charge)/(Amount Financed)*100$=$18.29, and we see to which annual porcentage rate it corresponds in the first row
Answer: 11.25%
we hat is the measure of ABC Is15
Answer:
Step-by-step explanation:
we know that
The compound interest formula is equal to
where
A is the Final Investment Value
P is the Principal amount of money to be invested
r is the rate of interest in decimal
t is Number of Time Periods
n is the number of times interest is compounded per year
in this problem we have
substitute in the formula above