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son4ous [18]
3 years ago
5

Solve 1)3x-7=35? 2)22=7-3a 3)-d+7=3 4)2x+23=49 5)-c+2=5

Mathematics
2 answers:
kondaur [170]3 years ago
8 0
1)\\3x-7=35\\3x-7+7=35+7\\3x=42\\3x=3\cdot14\ /:3\\x=14\ \ \ \leftarrow\ \ \ Answer\\\\
2)\\22=7-3a\\22-22+3a=7-3a-22+3a\\3a=-15\\3a=3\cdot(-5)\ /:3\\a=-5\ \ \ \leftarrow\ \ \ Answer\\\\3)\\-d+7=3\\-d+7-7=3-7\\-d=-4\\d\cdot(-1)=4\cdot(-1)\ /:(-1)\\d=4\ \ \ \leftarrow\ \ \ Answer\\\\

4)\\2x+23=49\\  2x+23-23=49-23\\2x=26\\2\cdot x=2\cdot 13\ /:2\\x=13  \ \ \ \leftarrow\ \ \ Answer\\\\ 
5)-c+2=5\\  -c+2-2=5-2\\ -c=3\\ c\cdot(-1)=-3\cdot(-1)\ /:(-1)\\c=-3 \ \ \ \leftarrow\ \ \ Answer
astra-53 [7]3 years ago
7 0
1)\ 3x-7=35\ \ \ |add\ 7\ to\ both\ sides\\\\3x=42\ \ \ \ |divide\ both\ sides\ by\ 3\\\\\boxed{x=14}\\-------------------------\\2)\ 22=7-3a\\\\7-3a=22\ \ \ \ |subtract\ 7\ from\ both\ sides\\\\-3a=15\ \ \ \ \ |divide\ both\ sides\ by\ (-3)\\\\\boxed{a=-5}\\--------------------------

3)\ -d+7=3\ \ \ \ \ |subtract\ 7\ from\ both\ sides\\\\-d=-4\\\\\boxed{d=4}\\---------------------------\\\\4)\ 2x+23=49\ \ \ \ \ \ |subtract\ 23\ from\ both\ sides\\\\2x=26\ \ \ \ \ \ |divide\ both\ sides\ by\ 2\\\\\boxed{x=13}\\---------------------------\\5)\ -c+2=5\ \ \ \ \ \ |subtract\ 2\ from\ both\ sides\\\\-c=3\\\\\boxed{c=-3}
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The equation of the function in vertex form is y = -(x + 5)² + 4

<h3>What is quadratic equation?</h3>

A quadratic equation is a second-order polynomial equation in a single variable x , ax2+bx+c=0. with a ≠ 0 .

Given that the quadratic function has roots at -3 and -7 and a vertex at (-5,4).

We need to find the equation of the function in vertex form

equation of the function in vertex form.

As per the information given in the question,

The given roots of the function are -3 and -7,

y = a (x + 3) (x + 7)

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y = -(x + 5)² + 4

Hence, y = -(x + 5)² + 4  is the equation of the function in vertex form

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