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3 years ago

What is the complete factorization of x^2 - 6x + 9

Mathematics

1 answer:

Finger [1]3 years ago

4 0

Answer:

$(x-3)^{2}$

Step-by-step explanation:

Factor using the perfect square rule.

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Which of the following expressions shows how to rewrite 4 - 5 using the addtive inverse and displays the expression correctly on

Evgesh-ka [11]

Answer: 4 - 5 = 4 + (-5) = -1

Step-by-step explanation: You have to make the 5 into a negative number using parenthesis and do the math.

5 0

2 years ago

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Find all solutions of the given system of equations (If the system is infinite many solution, express your answer in terms of x)

lisov135 [29]

Answer:

(a) The system of the equations $\left \{ {2x-3y\:=3} \atop {4x-6y\:=3}} \right.$ has no solution.

(b) The system of the equations $\left \{ {4x-6y\:=10} \atop {16x-24y\:=40}} \right.$ has many solutions $y=\frac{2x}{3}-\frac{5}{3}$

Step-by-step explanation:

(a) To find the solutions of the following system of equations $\left \{ {2x-3y\:=3} \atop {4x-6y\:=3}} \right.$ you must:

Multiply $2x-3y=3$ by 2:

$\begin{bmatrix}4x-6y=6\\ 4x-6y=3\end{bmatrix}$

Subtract the equations

$4x-6y=3\\-\\4x-6y=6\\------\\0=-3$

0 = -3 is false, therefore the system of the equations has no solution.

(b) To find the solutions of the system $\left \{ {4x-6y\:=10} \atop {16x-24y\:=40}} \right.$ you must:

Isolate x for $4x-6y=10$

$x=\frac{5+3y}{2}$

Substitute $x=\frac{5+3y}{2}$ into the second equation

$16\cdot \frac{5+3y}{2}-24y=40\\8\left(3y+5\right)-24y=40\\24y+40-24y=40\\40=40$

The system has many solutions.

Isolate y for $4x-6y=10$

$y=\frac{2x}{3}-\frac{5}{3}$

3 0

2 years ago

Help plz it’s 50 points help

abruzzese [7]

Answer:

Step-by-step explanation:

4 0

2 years ago

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BRAINLIEST for whoever gets this correct!

ratelena [41]

Answer:

Step-by-step explanation:

5 0

3 years ago

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What is interest earned on 3500 invested at 6% compounded quarterly or 12 years

enyata [817]

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$3500\\
r=rate\to 6\%\to \frac{6}{100}\to &0.06\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, thus four}
\end{array}\to &4\\
t=years\to &12
\end{cases}
\\\\\\
A=3500\left(1+\frac{0.06}{4}\right)^{4\cdot 12}\implies A=3500(1.015)^{48}$

so, the interest earned then will be A - 3500.

6 0

2 years ago