Y=-4x - 24
I hope this helps you :)
To evaluate the combination we proceed as follows:
21C3
Given nCk we shall have:
n!/[(n-k)!k!]
thus plugging the values in the expression we get:
21!/[(21-3)!3!]
=21!/(18!×3!)
=1330
Answer: 1330
Section J has 20 rows....each row has 15 seats....so section J has (20 * 15) = 300 seats. If each seat costs $ 18, and all the seats are sold, then the amount of money collected would be : (300 * 18) = $ 5,400 <=
Hello!
First you have to find the total of the items he bought
382 + 12 + 6.14 = 400.14
Then you apply the tax rate
400.14 * 1.0825 = 433.15155
We round this to 433.15
The answer is $433.15
Hope this helps!
