Since there is no repetition allowed, there are 10 possibilities for the 1st digit, 9 for the 2nd, 8 for the 3rd, and 7 for the 4th. This gives a total of (10)(9)(8)(7) = 5040 four-digit codes.
For all odd digits to be used, there are 5 possibilities for the 1st digit (1,3,5,7,9), 4 for the 2nd, 3 for the 3rd, 2 for the 4th. This gives a total of (5)(4)(3)(2) = 120 codes that only use odd digits.
Therefore there are 5040 - 120 = 4920 codes that do not consist of all odd digits. The probability is 4920/5040 = 41/42.
<h3>
Answer: 79 full rotations</h3>
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Explanation:
150 cm = 150/100 = 1.5 m
The wheel has a diameter of 1.5 meters
The circumference of the wheel is
C = pi*d
C = pi*1.5
C = 1.5pi
C = 4.71238898038469
I'm using my calculator's stored version of pi to get the most accuracy.
Then we divide the 376.8 over the circumference found
(376.8)/(4.71238898038469) = 79.9594434093682
Despite being very close to 80, we must round down to 79 because we don't have enough to get that full 80th rotation. In other words, we have 79 full rotations and then some change leftover.
Though for the sake of simplicity, I can see how it's useful to say "about 80 rotations" if 79 seems a bit clunky. I'll stick with 79 however. Let me know if your teacher instructs otherwise.
6.4 months Because 10% of $1,100 is $110
multiply 110 by 6.4 and you get 704
so 6.4 months
TU=AB since they are congruent figure. So AB=13
